In the first shell there is 2 electrons and on the second shell there is 4 elections.
Answer: 1Ca + 2O + 2H
Explanation:
Ca is 1 since there is no subscript
O and H each have 2 because the subscript 2 is outside the parenthesis so you multiply their subscript (1) by 2
Answer:
8.194 Mev per nucleon
Explanation:
Mass of Barium = 135.905 amu
number of proton = 56, number of neutron = 80
Md = (Mp + Mn) - Mb Mp is the mass of proton, Mn is the mass of neutron, Mb is the mass of barium and Md is the mass defect
Mn = 1.00867 amu Mp = 1.00728 amu
Md = ( 56 ( 1.00728) + 80 ( 1.00867) = 137.1013 - 135.905 =1.1963 amu
Md = 1.1963 × 1 ÷ ( 6.02214 × 10 ²⁶ amu ) = 1.9865 × 10 ⁻²⁷ kg
Energy = mc² = 1.9865 × 10 ⁻²⁷ kg × (2.99792 × 10 ⁸ m/s)²
E= 1.78537 × 10⁻¹⁰ J
to convert to Mev
1.78537 × 10⁻¹⁰ × 6241457006000 = 1114.33 Mev
binding energy per nucleon = 1114.33 / 136 =8.194 Mev per nucleon
To let you know what you are working with. if you have a wrong name for a graph then you will get the wrong answer
