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2 years ago

10

Calculate the current in the 8-W resistor of Figure below by using Thevenin’s theorem. What will be its value of connections of

6V battery are reversed

1 answer:

kvv77 [185]2 years ago

7 0

solution from c hegg. hope it helps. see photos explanation

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Limestone scrubbing is used to remove SO2 in a flue gas desulfurization (FGD) system. Relevant reactions are given below. A lime

lord [1]

Answer:

hello some data related to your question is missing attached below is the missing data

answer : 63700 Ib/hr

Explanation:

Given data :

Limestone mix : consists of 94% CaCO3 and 6% inert material

Actual feed rate = 36,000 Ib/hr

SO2 in flue gas = 20,314 Ib/hr

FGD efficiency = 97%

resulting sludge contains 58% solids

<u>Calculate the Total sludge production rate </u>

First : determine SO2 removed in sludge

= 0.97 * 20314

= 19704.58 Ib/hr

next : moles of SO2 removed

= 19704.58 / 64 Ib/ Ib mol

= 307.88 Ib mol / hr

also moles of CaSO3 produced = 307.88 Ib mol / hr

mass of CaSO3 = 307.88 * 120 = 36946.09 Ib/hr

Therefore Total sludge production rate

= 36946.09 / 0.58

= 63700.15 Ib/hr

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7 0

2 years ago

A steam power plant with a power output of 230 MW consumes coal at a rate of 60 tons/h. If the heating value of the coal is 30,0

NARA [144]

Answer:

$\eta =46\%$

Explanation:

Hello!

In this case, we compute the heat output from coal, given its heating value and the mass flow:

$Q_H=60\frac{tons}{h}*\frac{1000kg}{1ton}*\frac{1h}{3600s}*\frac{30,000kJ}{kg}\\\\Q_H=500,000\frac{kJ}{s}*\frac{1MJ}{1000J} =500MW$

Next, since the work done by the power plant is 230 MW, we compute the efficiency as shown below:

$\eta =\frac{230MW}{500MW}*100\% \\\\\eta =46\%$

Best regards!

7 0

2 years ago

A 40kg steel casting (Cp=0.5kJkg-1K-1) at a temperature of 4500C is quenched in 150kg of oil (Cp=2.5kJkg-1K-1) at 250C. If there

podryga [215]

Of the oil I hope this help

4 0

3 years ago

The mechanical advantage of a screw is always ____________________ than/to 1. Question 5 options: less, greater, equal, none of

torisob [31]

Answer:well u can use to make a shelter but that's all I can think of ??

Explanation:

3 0

2 years ago

A bar having a length of 5 in. and cross-sectional area of 0. 7 in.2 is subjected to an axial force of 8000 lb. If the bar stret

andrew11 [14]

The modulus of elasticity is 28.6 X 10³ ksi

<u>Explanation:</u>

Given -

Length, l = 5in

Force, P = 8000lb

Area, A = 0.7in²

δ = 0.002in

Modulus of elasticity, E = ?

We know,

Modulus of elasticity, E = σ / ε

Where,

σ is normal stress

ε is normal strain

Normal stress can be calculated as:

σ = P/A

Where,

P is the force applied

A is the area of cross-section

By plugging in the values, we get

σ = $\frac{8000 X 10^-^3}{0.7}$

σ = 11.43ksi

To calculate the normal strain we use the formula,

ε = δ / L

By plugging in the values we get,

ε = $\frac{0.002}{5}$

ε = 0.0004 in/in

Therefore, modulus of elasticity would be:

$E = \frac{11.43}{0.004} \\\\E = 28.6 X 10^3 ksi$

Thus, modulus of elasticity is 28.6 X 10³ ksi

6 0

2 years ago