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Nata [24]
3 years ago
5

Question 25 of 25 What is a limitation of modeling the effect of gravity on a falling object by using a ball dropped from differ

ent heights? A. Air slows down the fall of any object, including the ball. B. The weight of the ball can vary. C. Gravity varies slightly at different heights. D. The height that a ball bounces is affected by the height from which it was dropped.​
Physics
2 answers:
agasfer [191]3 years ago
5 0

Answer:

Air slows down The fall of any object including a ball.

Ahat [919]3 years ago
5 0

Answer:A

Explanation: I got it right on my test hope it helps

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If you ride your bike 20 miles and it takes you 120 minutes,what is your average speed
Alexus [3.1K]
120 minutes=2 hours
20/2= 10mph
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3 years ago
If the voltage across a circuit of constant resistance is doubled, the power dissipated by that circuit will
densk [106]

Answer:

The voltage will quadruple

Explanation:

The power dissipated in a circuit is given by

P=\frac{V^2}{R}

where

V is the voltage

R is the resistance

In this problem, the voltage across the circuit is doubled:

V' = 2V

So the new power dissipated is

P'=\frac{V'^2}{R}=\frac{(2V)^2}{R}=4\frac{V^2}{R}=4 P

so, the power dissipated will quadruple.

6 0
3 years ago
A 7300 kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.20 m/s2 and feels no appreci
Simora [160]

Answer:

Explanation:

We shall first calculate the velocity at height h = 575 m .

acceleration a = 2.2 m /s²

v² = u² + 2 a s

u is initial velocity , v is final velocity , s is height achieved

v² = 0 + 2 x 2.2 x 575

v = 50.3 m /s

After 575 m , rocket moves under free fall so g will act on it downwards

If it travels further by height H

from the relation

v² = u² - 2 g H

v = 0 , u = 50.3 m /s

H = ?

0 = 50.3² - 2 x 9.8 H

H = 129.08 m

Total height attained by rocket

= 575 + 129.08

= 704.08 m .

4 0
2 years ago
At an instant when a particle of mass 80 g has a velocity of 25 m/s in the positive y direction, a 75-g particle has a velocity
dalvyx [7]

Answer:

16 m/s

Explanation:

Given that

y momentum = 0.080 *25 = 2

x momentum = 0.075*20 = 1.5

total momentum = √(4 + 2.25)

Total momentum = √6.25

Total momentum = 2.5

total mass = mass of x and y momentum = 0.075 + 0.080 = 0.155

speed of mass center = total momentum / total mass = 2.5/0.155 = 16.

And thus, the speed of the center of mass of this two-particle system at this instant is 16 m/s

7 0
3 years ago
I am starting out as a pilot. What single engine make of airplane should I get (Cheaper to bye one and train than to rent it)?
hichkok12 [17]
You have to make sure you know what your doing plus if you have your license and stuff to fly you have to practice on a 25 minute course
7 0
3 years ago
Read 2 more answers
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