I need help people :0

At which temperature is water in its gas phase (water vapor)?

tankabanditka [31]

Answer: (Assuming we’re going by degrees Fahrenheit) I’d say 140.

Explanation: -40 would be beyond freezing point for water which is 32 degrees Fahrenheit and 40 would nearly be freezing point. For water to transform into its gas phase, the temperature would need to be greater. Therefore, 140 degrees Fahrenheit makes the most sense.

Although I did search it up and 212 degrees Fahrenheit (100 degrees Celsius) is the proven temperature at which water transforms into water vapor so... not sure if there’s more to the question or I’m interpreting the question wrong.

4 0

3 years ago

Who has taken chemistry, if you have I want to know how were you successful (if u were) because currently I am taking it and I’m

Andreas93 [3]

My number one tip is to STUDY! I know it sucks, but once you're in high school, it's going to become a part of your routine every single day. Even if you study right now, keep on doing it over and over and over. Trust me! It'll help. Also, get a tutor! Maybe someone you know is doing well and you could ask them to help, or you could ask a student who was in your class and passed. My number one advice is to just keep working hard. I get it; chemistry is HARD. You'll get there!

5 0

3 years ago

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The solubility of nitrogen gas at 25°C and a nitrogen pressure of 522 mmHg is 4.7 × 10 –4 mol/L. What is the value of the Henry'

Anestetic [448]

Answer:

6.8 × 10⁻⁴ mol/L.atm

Explanation:

Step 1: Given data

Solubility of nitrogen gas at 25°C (S): 4.7 × 10⁻⁴ mol/L

Partial pressure of nitrogen gas (P): 522 mmHg

Step 2: Convert the partial pressure of nitrogen to atm

We will use the relationship 1 atm = 760 mmHg.

$522mmHg \times \frac{1atm}{760mmHg} = 0.687atm$

Step 3: Calculate the value of the Henry's Law constant (k)

We will use Henry's law.

$S = k \times P\\k = \frac{S}{P} = \frac{4.7 \times 10^{-4}mol/L }{0.687atm} = 6.8 \times 10^{-4} mol/L.atm$

3 0

4 years ago

What mass of limestone (in kg) would be required to completely neutralize a 15.5 billion-liter lake that is 1.7×10^−5 M in H2SO4

Alinara [238K]

The complete balanced chemical reactions are:

HNO3 => CaCO3 + 2HNO3 → Ca(NO3)2 + H2O + CO2(g)

H2SO4 => CaCO3 + H2SO4 → CaSO4 + H2O + CO2(g)

So we see that 1 mole of CaCO3 is needed for 2 moles of HNO3 and similarly to 1 mole of H2SO4.
The number of moles can be calculated as the product of volume and molarity, so:

moles H2SO4 = 1.7×10^−5 M * (15.5 x 10^9 L) = 263,500 mol H2SO4

moles HNO3 = 8.9×10^−6 M * (15.5 x 10^9 L) = 137,950 mol HNO3

So the total moles of CaCO3 required is:

moles CaCO3 = 263,500 mol * 1 + 137,950 mol * (1/2)

moles CaCO3 = 332,475 mol

The molar mass of CaCO3 is 100.086 g/mol, so the mass is:

mass CaCO3 = 332,475 mol * 100.086 g/mol

mass CaCO3 = 33,276,092.85 g = 33.3 x 10^3 kg

5 0

4 years ago

What is the definition of a lewis base?

Tom [10]

A substance that donates electrons to form a covalent bond. So the answer is B

8 0

3 years ago

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