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Snowcat [4.5K]
3 years ago
12

A ball is launched with an initial horizontal velocity of 10.0 meters per second. It takes 500 milliseconds for the ball to reac

h its maximum height.
Determine the maximum horizontal distance that the ball will travel.
Calculate the initial vertical velocity of the ball.
Physics
1 answer:
hichkok12 [17]3 years ago
5 0

Answer:

500ms times 2 would be when the ball reaches the max horizontal distance.

Then to find the angle, use the formula of time to reach max height t = u sin theta / g . With t being the max height time 500ms, u being 10m/s

For initial vertical velocity just use u sin theta.

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS AND I NEED ALL CORRECT ANSWERS ONLY!!!
Travka [436]

Yes you are correct...I dont think you need to do this? You are getting them all right but now your just wasting points..

But anyways you are correct. ♡♡

5 0
4 years ago
Viscosity: Blood is about 4 to 5 times ____________ viscous than water. Viscosity of blood depends upon the amount of dissolved
kherson [118]

Answer:more, increased

Explanation:

Blood is four to five times more viscous than water.

Viscosity depends upon dissolved substances in blood and it increases as the amount is increases or if the fluid in the blood decreases.

Viscosity is the resistance offered by liquid to the flow and it also depends upon temperature and it decreases with increase in temperature.      

8 0
3 years ago
When the starter motor on a car is engaged, there is a 300 A cunent in the wires between the bauery and the motor. Suppose the w
docker41 [41]

Answer:

diameter of transmission is 3.473 mm

Explanation:

given data

current = 300 A

total wire length = 1.0 m

voltage drop = 0.55 V

solution

as here Resistivity of copper is = 1.68 × 10^{-8} ohm- m

so we get here resistance of wire that is

resistance = \frac{V}{I}    ..............1

R = \frac{0.55}{310}  

R = 1.774 × 10^{-3}  ohm

and now we get diameter of wire that is

R = \frac{\rho l}{A}    .............2

\pi \frac{d^2}{4} = \frac{\rho l}{R}    

d² = \frac{4\rho l}{\pi R}     ...............3

put here value

d² = \frac{4\times 1.68\times 10^{-8} \times 1}{\pi \times 1.774\times 10^{-3}}  

d = \sqrt{12.064\times 10^{-6}}

d = 3.473 × 10^{-3} m

d = 3.473 mm

so diameter of transmission is 3.473 mm

4 0
4 years ago
Describe how Newton’s third law applies to the box and the table.
Snowcat [4.5K]

Answer:

the box has vertical force on the table

Explanation:

There can be no single isolated force, for every action there must be a force of reaction of ingual magnitude and direction, but in the opposite direction

3 0
4 years ago
Read 2 more answers
Two students try to move a heavy box. One pushes with the force of the 80N while the other pulls with a force of 40N in the same
alekssr [168]

Answer:

<em>Good Luck!</em>

Explanation:

Force applied by first student (F1) = 80 N

Force applied by the second student (F2) = 40 N

Displacement (d) = 10 m

Work done by first student (W1) = F1d = 80*10 = 800 J

Work done by second student (W2) = F2d = 40*10 = 400 J

Hence, the work done by the pushing student is 800 J and that by pulling student is

<h2> <u><em>400 J</em></u></h2>
5 0
3 years ago
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