Answer:
(a)
(b)
(c) 4.43 m/s
(d) 2 m/s
Explanation:
Using the attached image, point 4 is point A
Since potential energy PE=mgh where m is mass, g is acceleration due to gravity and h is height.
The height is 100cm equivalent to 1 m
Substituting 2g equivalent to 0.002 Kg for m, for g and 1 m for h we obtain
(b)
Kinetic energy is given by
KE=0.5mv^{2} where v is the velocity, m is mass and KE is kinetic energy
Substituting m for 0.002 Kg and
(c)
As already illustrated in part b
(d)
From the law of conservation of energy
Energy at point A equals energy at point C
Newton’s first Law is law of inertia or resistance to change of motion. Objects in motion tend to stay in motion or an object at rest tends to stay at rest, unless acted on by an outside force.
Newton’s second Law is F=ma is equal to the rate of change of momentum with respect to time dp/dt. This means force is equal to mass times acceleration or F= mass*(d^2x/dt^2)
Newton’s third Law is for every force there is an equal and opposite force. Meaning if I push on the ground, the ground pushes back on me equally an opposite.
Hope this helps you understand Newton’s three laws of motion. Any questions please ask!!
Thank you!!
Force = mass * acceleration, with units kg*m / second squared, or the more commonly the Newton, N. Assuming objects freely fall due to gravity at 9.8 m/second squared, and zero air resistance force opposing the freely falling object, 1 kg * 9.8 m/second squared = 9.8 N = force on the ball.
the answer is letter B “the materials with the greatest specific heat”
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Answer:
2.73×10¯³⁴ m.
Explanation:
The following data were obtained from the question:
Mass (m) = 0.113 Kg
Velocity (v) = 43 m/s
Wavelength (λ) =?
Next, we shall determine the energy of the ball. This can be obtained as follow:
Mass (m) = 0.113 Kg
Velocity (v) = 43 m/s
Energy (E) =?
E = ½m²
E = ½ × 0.113 × 43²
E = 0.0565 × 1849
E = 104.4685 J
Next, we shall determine the frequency. This can be obtained as follow:
Energy (E) = 104.4685 J
Planck's constant (h) = 6.63×10¯³⁴ Js
Frequency (f) =?
E = hf
104.4685 = 6.63×10¯³⁴ × f
Divide both side by 6.63×10¯³⁴
f = 104.4685 / 6.63×10¯³⁴
f = 15.76×10³⁴ Hz
Finally, we shall determine the wavelength of the ball. This can be obtained as follow:
Velocity (v) = 43 m/s
Frequency (f) = 15.76×10³⁴ Hz
Wavelength (λ) =?
v = λf
43 = λ × 15.76×10³⁴
Divide both side by 15.76×10³⁴
λ = 43 / 15.76×10³⁴
λ = 2.73×10¯³⁴ m
Therefore, the wavelength of the ball is 2.73×10¯³⁴ m.