Answer:
The correct answer is a rarefaction.
Explanation:
Sound waves are longitudinal waves that propagate in a medium, such as air. As the vibration continues, a series of successive condensations and rarefactions form and propagate from it. The pattern created in the air is something like a sinusoidal curve to represent a sound wave.
There are peaks in the sine wave at the points where the sound wave has condensations and valleys where it has rarefactions.
Have a nice day!
Answer:
Tides on our planet are caused by the gravitational pull of the Moon and Sun. Earth's oceans "bulge out" because the Moon's gravity pulls a little harder on one side of our planet (the side closer to the Moon) than it does on the other. The Sun's gravity raises tides, too, but lunar tides are twice as big.
Answer:
Explanation:
The dimension less constants are the constants having no dimensions and also have a constant value.
For example, 1, 2, 3... numbers, e (exponent), 
, etc.
The dimension less variables are the variables having no dimensions.
For example, refractive index, angle, strain, etc.
Answer: the minimum spacing that must be there between two objects on the earth's surface if they are to be resolved as distinct objects by this telescope 6.45 cm
Explanation:
Given that;
diameter of the mirror d = 1.7 m
height h = 180 km = 180 × 10³ m
wavelength λ = 500 nm = 5 × 10⁻⁹ m
Now Angular separation from the peak of the central maximum is expressed as;
sin∅= 1.22 λ / d
sin∅ = (1.22 × 5 × 10⁻⁹) / 1.7
sin∅ = 3.588 × 10⁻⁷
we know that;
sin∅ = object separation / distance from telescope
object separation =
sin∅ × distance from telescope
object separation = 3.588 × 10⁻⁷ × 180 × 10³
object separation =6.45 × 10⁻² m
then we convert to centimeter
object separation = 6.45 cm
Therefore the minimum spacing that must be there between two objects on the earth's surface if they are to be resolved as distinct objects by this telescope 6.45 cm
Answer:
5.3 × 10^(-8) m
Explanation:
We are given;
Shear force; F = 400 N
Length of cube; L_o = 30 cm = 0.3 m
Shear modulus; S = 2.5 × 10^(10) N/m²
Now,the resulting relative displacement can be gotten from the formula;
F = A × S × Δx/L_o
Where Δx is resulting relative displacement
A is area.
Area of cube = (L_o)² = 0.3² = 0.09
Thus, making Δx the subject, we have;
Δx = (F × L_o)/(A × S)
Plugging in the relevant values;
Δx = (400 × 0.3)/(0.09 × 2.5 × 10^(10))
Δx = 5.3 × 10^(-8) m
