That due to the specific tasks that needs to be accomplished by each program to make an all encompassing program would be inefficient and full of bugs
Answer:
Stabilizer with area = 14 cm2
Explanation:
i dont know why but its right
Answer:
chilhowee to North Carolina state line
Answer:
t=5.5 mm
Heat dissipation per unit length = 90.477 W/m
Explanation:
Given that
Diameter d = 5 mm ⇒r = 2.5 mm
Conductivity of insulated material K = 0.16 W/mK
Heat transfer coefficient = 20
When thickness reaches up to critical radius of insulation then heat dissipation will be maximum
We know that critical radius of insulation of wire is given as follow
Now by putting the values
So the thickness of insulation
t=8-2.5 mm
t=5.5 mm
As we know that heat transfer due to convection given as follows
Q = hAΔ T
Q=20 x 2 x π x 0.008 x (120-30)
Q = 90.477 W/m
So heat dissipation per unit length = 90.477 W/m
Answer:
b) Power to bulb = 0.5184 watt
Power into the battery = - 0.5184 watt
c) T = 19290.123 sec
Explanation:
Given data:
Voltage = 7.2 V
energy = 10,000 J
Resistance = 100 ohm
a) associated circuit is shown in attachment
b)
Power = 0.5184 watt
Power into the battery = - 0.5184 watt
c)
T = 19290.123 sec