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bekas [8.4K]
3 years ago
7

Efficiency of a machine is lesser than 100% , Why?

Physics
1 answer:
astra-53 [7]3 years ago
4 0

Answer:

Efficiency is the percent of work put into a machine by the user (input work) that becomes work done by the machine (output work). The output work is always less than the input work because some of the input work is used to overcome friction. Therefore, efficiency is always less than 100 percent.

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H) Find the inverse Laplace transforms of the equation. When the X(s) =1 /(s²+9s+20)​
Anastasy [175]

Answer:

e^-4t e^-5t

Explanation:

solving s²+9s+20 quadratically we have (s+4)(s+5)

x(s) can be written as x(s) =(1/s+4)(1/s+5)

if we take the laplace inversve

L-¹ (s)=L-1(1/s+4) L-1(1/s+5)

we have e^-4t e^-5t

7 0
1 year ago
An unstable atomic nucleus of mass 1.58 10-26 kg initially at rest disintegrates into three particles. One of the particles, of
lara31 [8.8K]

Answer:

a The velocity of the third particle is v_3 = (-15.629*10^{6}i -14.45*10^{6}j)\ m/s

b The total kinetic energy increase E = 6.50 *10^{-13} J

Explanation:

To solve this question we are going to be using the concept of conservation of momentum which is mathematically represented as

            m_1v_1 +m_2v_2 +m_3v_3 = 0

From the question

        Mass of  unstable atomic nucleus m_0= 1.58 *10^{-26} kg

        Mass of  x-axis particle m_1 = 8.44* 10^{-27} kg

        Velocity of x-axis particle v_ 1 =  4.00* 10^6 m/s

         Mass of  y-axis particle  m_2 =5.20* 10^{-27} kg

            Velocity of y-axis particle  v_2 = 6.00 *10^6 m/s

 Since the initial mass is known we can obtain the mass of the third particle  

 Using the conservation of mass mathematical expression

                m_3 = m_0 - (m_1 +m_2)

                  m_3 = 1.58 *10^{-26}  - ( 8.44* 10^{-27} + 5.20* 10^-27)

                        = 2.16 *10 ^{-27}kg

Using the mathematical expression above for conservation of momentum

               (8.44 * 10^{-27})( 4.00* 10^6i) + (5.20 *10^{-27})(6.00* 10^6j) +(2.16*0^{-27})v_3 =0

            v_3 = (-15.629*10^{6}i -14.45*10^{6}j)\ m/s

The above is the vector solution now to obtain the value in numeric form we evaluate the magnitude of the vector

         Mag  = \sqrt{(15.629*10^6)^2 +(14.45*10^6)^2}

                = 21.285*10^6 \ m/s

To obtain the total increase in  kinetic energy which is mathematically represented as

         E = \frac{1}{2}m_1v_1 +  \frac{1}{2}m_2v_2 + \frac{1}{2} m_3 v_3

         E =\frac{1}{2} [(5.20*10^{-27})(6.0*0^{6})^2 + (8.44*10^{-27})(4.00*10^6)^2+\\\\(2.16*10^{-27})(21.285*10^6)^2]

              = 6.50 *10^{-13} J

5 0
3 years ago
Vittorio needs to clean the dusty mirror hanging on the wall beforehe can use it, but he would like to clean as little of the mi
Inessa [10]

Answer:

The drawing is attached below.

Explanation:

According to the drawing, we can see that the point "0" marked on the mirror, is the point that allows the formation of an angle between Vittorio's eyes and the place where his shirt logo is. In summary, the point on the mirror that needs to be cleaned, so that Vittorio can see only the logo of his shirt, is the point that represents equal vertical distances between Vittorio's eyes and the shirt's logo, since these distances present the same angle.

6 0
4 years ago
Which of the following are located outside the nucleus of an atom? Select all that
dmitriy555 [2]
Electrons are located outside the nucleus
3 0
3 years ago
BRAINLEST TO SOMEONE WHO ACTUALLY ANSWERS AND FREE 100 POINTS TO REAL ANSWER 2. Using the average time, calculate the oscillatio
andrezito [222]

Answer:

IM SO SORRY :((

Explanation:

7 0
3 years ago
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