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Alenkasestr [34]
3 years ago
14

Answer for gym class please

Physics
1 answer:
Anton [14]3 years ago
6 0
Rating of perceived exertion
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A worker on the roof of a house drops his 0.46 kg hammer, which slides down the roof at constant speed of 9.88 m/s. The roof mak
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Answer:

The horizontal distance travelled in that time lapse is 12.94 m

Explanation:

In order to solve this problem, we'll need:

  1. The horizontal speed
  2. the time the hammer takes to fall from the roof to the ground

At the lowest point of the roof, the hammer has a 9.88 m/s speed that makes an angle of 27° with the horizontal, so we can calculate the horizontal and vertical speed with trigonometry. If we take right as x positive and down as y positive we get

v_{x}=v*cos(27)=9.88 m/s *cos(27)=8.80 m/s \\v_{y}=v*sen(27)=9.88 m/s *sen(27)=4.49 m/s

Now, we make two movement equation as we have a URM (no acceleration) in x and an ARM (gravity as acceleration) in y. We will wisely pick the lowest point of the roof as the origin of coordinates

x(t)=8.8 m/s *t

y(t)=4.49m/s*t+\frac{1}{2}*9.8m/s^{2}*t^{2}

Now we calculate the time the hammer takes to get to the floor

17.1m=4.49m/s*t+\frac{1}{2}*9.8m/s^{2}*t^{2}\\t=1.47s or t=-2.38s

Now, we keep the positive time result and calculate the horizontal distance travelled

x(1.47s)=8.8m/s*1.47s=12.94m

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