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2 years ago

If car A passes car B, then car A must be

Physics

1 answer:

Tcecarenko [31]2 years ago

4 0

Answer:

B. moving faster than car B, but not necessarily accelerating

Explanation:

Velocity is the speed of something. So car A's velocity is greater than car B but does not mean car A is accelerating.

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Reception devices pick up the variation in the electric field vector of the electromagnetic wave sent out by the satellite. Give

Keith_Richards [23]

Complete Question

A satellite in geostationary orbit is used to transmit data via electromagnetic radiation. The satellite is at a height of 35,000 km above the surface of the earth, and we assume it has an isotropic power output of 1 kW (although, in practice, satellite antennas transmit signals that are less powerful but more directional).

Reception devices pick up the variation in the electric field vector of the electromagnetic wave sent out by the satellite. Given the satellite specifications listed in the problem introduction, what is the amplitude E0 of the electric field vector of the satellite broadcast as measured at the surface of the earth? Use ϵ0=8.85×10^−12C/(V⋅m) for the permittivity of space and c=3.00×10^8m/s for the speed of light.

Answer:

The electric field vector of the satellite broadcast as measured at the surface of the earth is $E_o = 6.995 *10^{-6} \ V/m$

Explanation:

From the question we are told that

The height of the satellite is $r = 35000 \ km = 3.5*10^{7} \ m$

The power output of the satellite is $P = 1 \ KW = 1000 \ W$

Generally the intensity of the electromagnetic radiation of the satellite at the surface of the earth is mathematically represented as

$I = \frac{P}{4 \pi r^2}$

substituting values

$I = \frac{1000}{4 * 3.142 (3.5*10^{7})^2}$

$I = 6.495*10^{-14} \ W/m^2$

This intensity of the electromagnetic radiation of the satellite at the surface of the earth can also be mathematically represented as

$I = c * \epsilon_o * E_o^2$

Where $E_o$ is the amplitude of the electric field vector of the satellite broadcast so

$E_o = \sqrt{\frac{2 * I}{c * \epsilon _o} }$

substituting values

$E_o = \sqrt{\frac{2 * 6.495 *10^{-14}}{3.0 *10^{8} * 8.85*10^{-12}} }$

$E_o = 6.995 *10^{-6} \ V/m$

4 0

3 years ago

a horse moves a sleigh 1.00 kilometers by applying a horizontal 2000 Newton force on its harness for 45 minutes. what is the pow

tatyana61 [14]

-- If 2,000 newtons of force were applied through a distance of 1,000 meters,
then 2,000,000 newton-meters = 2,000,000 joules of work were done.

-- 45 minutes = (45 x 60) = 2,700 seconds

-- Power = (work) / (time) = (2,000,000 j) / (2,700 s) = <u>740.74 watts</u>

Interestingly, that's almost exactly 1 horsepower. (0.99295... of 746 watts)

8 0

3 years ago

A motor cycle travelling at 10 m/s accelerates at 4m/s(squared) for 8s.

Sever21 [200]

10 x 4^2 = 160 / 8..

V = 20m/s...

...x 8 = 100 miles,meters, metric what ever m stands for after 8 seconds.

This is my guess since the problem says 4m/s^2

V= distance/ ST (traveled/used)

8 0

3 years ago

A ball of a mass 0.3 kg is released from rest at a height of 8 m. How fast is it going when it hits the ground? Acceleration due

Vaselesa [24]

In order to solve this problem, there are two equations that you need to know to solve this problem and pretty much all of kinematics. The first is that d=0.5at^2 (d=vertical distance, a=acceleration due to gravity and t=time). The second is vf-vi=at (vf=final velocity, vi=initial velocity, a=acceleration due to gravity, t=time). So to find the time that the ball traveled, isolate the t-variable from the d=0.5at^2. Isolate the t and the equation now becomes $\sqrt{(2d)/a}$ . Solving the equation where d=8 and a=9.8 makes the time $\sqrt{(2*8)/9.8}$ =1.355 seconds. With the second equation, the vi=0 m/s, the vf is unknown, a=9.8 m/s^2 and t=1.355 sec. Substitute all these values into the equation vf-vi=at, this makes it vf-0=9.8(1.355). This means that the vf=13.28 m/s.

8 0

3 years ago

Read 2 more answers

(c)

lys-0071 [83]

The answer is c. Twelve wants pass an obsessive frequency of the internet

7 0

3 years ago