Answer:
<h2>Solving elastic collisions problem the hard way</h2><h3 />
Explanation:
perfect drawing
We have that for the Question "the acceleration of the object at time t = 0.7 s is most nearly equal to which of the following?"
- it can be said that the acceleration of the object at time t = 0.7 s is most nearly equal to the slope of the line connecting the origin and the point where the graph where the graph crosses the 0.7s grid line
From the question we are told
the acceleration of the object at time t = 0.7 s is most nearly equal to which of the following?
Generally the equation for the Force is mathematically given as
F=\frac{F}{dx}
Therefore
F=-kdx
k=600Nm^{-1}
now
K.E=0.5x ds^2
K.E=600*(-0.1^2)
K.E=3J
Therefore
the acceleration of the object at time t = 0.7 s is most nearly equal to the slope of the line connecting the origin and the point where the graph where the graph crosses the 0.7s grid line
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If the field is in a vacuum, the magnetic field is the dominant factor determining the motion. Since the magnetic force is perpendicular to the direction of travel, a charged particle follows a curved path in a magnetic field. The particle continues to follow this curved path until it forms a complete circle. Another way to look at this is that the magnetic force is always perpendicular to velocity, so that it does no work on the charged particle. The particle’s kinetic energy and speed thus remain constant. The direction of motion is affected but not the speed.
A negatively charged particle moves in the plane of the paper in a region where the magnetic field is perpendicular to the paper (represented by the small × ’s—like the tails of arrows). The magnetic force is perpendicular to the velocity, so velocity changes in direction but not magnitude. The result is uniform circular motion.
Answer:
The magnitude is "3.8 m/s²", in the upward direction.
Explanation:
The given values are:
Mass,
m = 88 kg
Scale reads,
T = 900 N
As we know,
⇒ ![N=mg](https://tex.z-dn.net/?f=N%3Dmg)
On substituting the given values, we get
⇒ ![=88\times 9.8](https://tex.z-dn.net/?f=%3D88%5Ctimes%209.8)
⇒ ![=862.4 \ N](https://tex.z-dn.net/?f=%3D862.4%20%5C%20N)
Now,
⇒ ![T=mg-ma](https://tex.z-dn.net/?f=T%3Dmg-ma)
On substituting the given values in the above equation, we get
⇒ ![900=862.4-9.8 a](https://tex.z-dn.net/?f=900%3D862.4-9.8%20a)
On subtracting "862.4" from both sides, we get
⇒ ![900-862.4=862.4-9.8 a-862.4](https://tex.z-dn.net/?f=900-862.4%3D862.4-9.8%20a-862.4)
⇒ ![37.6=-9.8a](https://tex.z-dn.net/?f=37.6%3D-9.8a)
⇒ ![a=-\frac{37.6}{9.8}](https://tex.z-dn.net/?f=a%3D-%5Cfrac%7B37.6%7D%7B9.8%7D)
⇒
(upward direction)