Question

In a single-slit diffraction experiment, the slit is 0.1mm wide and is illuminatedby monochromatic light with a wavelength of 500 nm. The diffraction patternis observed on a screen 10 m away. What is the spacing between successiveminima in the pattern.

Answer 1

Answer:

$0.1$ m

Explanation:

$d$ = slit width = 0.1 mm = 0.1 x 10⁻³ m

$\lambda$ = wavelength of monochromatic light = 500 nm = 500 x 10⁻⁹ m

$D$ = Distance of the screen = 10 m

$w$ = Spacing between successive minima

Spacing between successive minima is given as

$w = \frac{2D\lambda }{d}$

Inserting the values given

$w = \frac{2(10)(500\times10^{-9}) }{0.1\times10^{-3}}$

$w = 0.1$ m