To calculate the molecular formula, convert the mass ratio into molar ratio as follows:
mass ratio of O:C=2:1
molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus, number of moles can be calculated as follows:
n=\frac{m}{M}
calculating ratio,
O:C=\frac{2 g}{16 g/mol}:\frac{1 g}{12 g/mol}=\frac{1}{8}:\frac{1}{12}=12:8=3:2
thus, molecular formula will be C_{2}O_{3}
Answer:
2HBr(g) → H₂ (g) + Br₂ (g)
2Al + Fe₂O₃ → 2Fe + Al₂O₃
2C₄H₆ + 11O₂ → 8CO₂ + 6H₂O
Ag + Pb₃(PO₄)₂ → No reaction
K₂CO₃ + Cal₂ → 2KI + CaCO₃
Explanation:
1st reaction:
2HBr(g) → H₂ (g) + Br₂ (g)
HBr produces hydrogen and bromine gas.
Second reaction:
2Al + Fe₂O₃ → 2Fe + Al₂O₃
Aluminium is more reactive than iron that's why it displace the iron from oxide and form aluminium oxide.
3rd reaction:
2C₄H₆ + 11O₂ → 8CO₂ + 6H₂O
Butyne burn in the presence of oxygen and produces carbondioxide and water.
4th reaction:
Ag + Pb₃(PO₄)₂ → No reaction
Because lead is more more reactive than silver that's why silver can not displace the lead to react with (PO₄)₂ .
5th reaction:
K₂CO₃ + Cal₂ → 2KI + CaCO₃
potassium carbonate react with calcium iodide and produces calcium carbonate and potassium iodide.
Answer:
C. Hb binds O2 more tightly than Mb.
Explanation:
<u>Hb and Mb are both oxygen carrier protiens which contain the heme group. Hb has 4 heme units in 1 moleucle which work via coperative effect. On the other hand, Mb has only one heme unit. </u>
<u>From above theory, statement A and B are correct.</u>
<u>Although the heme group of the Mb is identical to those of Hb, Mb has a higher affinity for carrying oxygen than hemoglobin.</u>
<u>Hence, Statement C is wrong.</u>
Thats why the function of hemoglobin is to transport oxygen and that of myoglobin is to store oxygen.
<u>When a curve is plotted between oxygen accepted and the pressure of the oxygen, Hb shows sigmoidal, whereas Mb shows hyperbolic oxygen saturation curves.</u><u> The statement D is correct.</u>
<u>Bohr effect and various factors decribe the statement : Hb-oxygen binding is dependent on physiological changes in pH, whereas Mb-oxygen binding is not. </u><u>The statement E is also correct.</u>
<h3>Answer:</h3>
Density = 1.22 g.mL⁻¹
<h3>Solution:</h3>
Data Given:
Mass = 22.4 g
Volume = 18.3 mL
Density = ??
Formula used;
Density = Mass ÷ Volume
Putting values,
Density = 22.4 g ÷ 18.3 mL
Density = 1.22 g.mL⁻¹
Answer:
[ H2O ]eq = 0.298 mol/L
Explanation:
- CH4(g) + H2O(g) ↔ CO(g) + 3H2(g)
∴ V = 0.501 L
∴ T = 1043 K
at equilibrium:
∴ n CH4 = 0.255 mol
⇒ [ CH4 ]eq = 0.255 mol / 0.501 L = 0.509 mol/L
∴ n CO = 0.169 mol
⇒ [ CO ]eq = 0.169 / 0.501 = 0.337 mol/L
∴ n H2 = 0.257
⇒ [ H2 ] eq = 0.257 / 0.501 = 0.513 mol/L
∴ Kc = [ H2 ]³ * [ CO ] / [ CH4 ] * [ H2O ] = 0.30
⇒ [ H2O ] = [ H2 ]³ * [ CO ] / [ CH4 ] * 0.30
replacing the value of the concentration in Kc:
⇒ [ H2O ] = ( 0.513 )³ * ( 0.337 ) / ( 0.509 ) * 0.30
⇒ [ H2O ] = 0.298 mol/L