Question

How much heat will be absorbed by a 26.3 g piece of aluminum (specific heat = 0.930 J/g･°C) as it changes temperature from 23.0°C to 67.0°C?

Answer 1

Answer:

$\boxed {\boxed {\sf 1076.196 \ Joules}}$

Explanation:

Since we are given the mass, specific heat, and temperature, we should use the following formula for heat energy.

$q=mc\Delta T$

The mass of the aluminum is 26.3 grams. Its specific heat is 0.930 Joules per gram degree Celsius. We need to find the change in temperature.

• The change in temperature is the difference between the initial temperature to the final temperature.
• The temperature changes from 23.0°C to 67.0°C, so the initial is 23 degrees and the final is 67 degrees.
• ΔT= final temperature - initial temperature
• ΔT= 67°C - 23°C
• ΔT= 44°C

Now we know all the values.

• m= 26.3 g
• c= 0.930 J/g °C
• ΔT= 44°C

Substitute the values into the formula.

$q= (26.3 \ g}) \times (0.930 \ J/g \textdegree C) \times (44 \textdegree C)$

Multiply the first two numbers together. The units of grams cancel.

$q= 24.459 \ J/ \textdegree C \times 44 \textdegree C$

Multiply again. This time, the units of degrees Celsius cancel.

$q=1076.196 \ J$

1076.196 Joules of heat will be absorbed by the piece of aluminum.