Answer:
Hmmm
Histamine is gotten from the De-carboxylation of Histidine
I'd go with false.
Histamine is NOT an essential amino acid
Option B is legit!
The correct answer to the question is:
<h3>1 O atom / 2 H atom</h3>
Sucrose is an organic compound with a molecular formula of C₁₂H₂₂O₁₁
With the molecular formula of sucrose, we can obtain the relationship of oxygen and hydrogen in the compound. This can be obtained as follow:
Sucrose => C₁₂H₂₂O₁₁
Hydrogen atom = 22
Oxygen atom = 11
<h3>Oxygen to Hydrogen =? </h3>
Oxygen to Hydrogen = 11 / 22
<h3>Oxygen to Hydrogen = 1/2</h3>
Therefore, the simple unit factor that relates the number of hydrogens in sucrose to the number of oxygens is:
1 O atom / 2 H atom
Learn more: brainly.com/question/7281916
Answer:
= 10 M or 10 moles/liter
Explanation:
Molarity is calculated by the formula;
Molarity = Moles/volume in liters
In this case;
The number of moles = 0.5 moles
Volume = 0.05 liters
Therefore;
Molarity = 0.5 moles/0.05 liters
= 10 M or 10 moles/liter
Thus the molarity is 10 M or 10 moles/liter
Answer:
they can become smaller or start fall apart or aroud
Explanation:
The element strontium (atomic number = 38) has four naturally-occurring isotopes. They are: Isotope / Percent Abundance / Mass (amu) Sr-84 / 0.56% / 83.9134 Sr-86 / 9.86% / 85.9093 Sr-87 / 7.00% / 86.9089 Sr-88 / 82.58% / 87.9056 The first thing to do is to convert all of the percentages to decimal fractions. To do that just move the decimal point two places to the left. Be careful, though...if the decimal is already at the front of the number you STILL have to move it two places. Add leading zeroes as necessary. 0.56% becomes 0.0056 9.86% becomes 0.0986 7.00% becomes 0.0700 82.58% becomes 0.8258 Next multiply each of the decimal fractions by the mass of each isotope. 0.0056 x 83.9134 = 0.47 0.0986 x 85.9093 = 8.47 0.0700 x 86.9089 = 6.08 0.8258 x 87.9056 = 72.59 Finally add the results to find the average atomic mass. 0.47 + 8.47 + 6.08 + 72.59 = 87.61 amu This agrees closely with the listed atomic mass for strontium, so I know I probably did my work correctly. I hope that helps