Scenario
1 answer:
Answer:
hello your question is poorly written and I have tried to understand it hence I will give a general diagram as related to your question
answer : attached below
Explanation:
Attached below is the required diagram of the situation you are trying to describe
let the wide receiver be ; W
Corner back = C
westward velocity = Vw
eastward velocity = Vc
at initial position X = Xw
x = 0 ( initial position )
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Answer:
6.53 m/s²
Explanation:
Let m₁ = 5 kg and m₂ = 10 kg. The figure is attached and free body diagrams of the objects are also attached.
Both objects (m₁ and m₂) have the same magnitude of acceleration(a). Let g be the acceleration due to gravity = 9.8 m/s². Hence:
T = m₁a (1)
m₂g - T = m₂a (2)
substituting T = m₁a in equation 2:
m₂g - m₁a = m₂a
m₂a + m₁a = m₂g
a(m₁ + m₂) = m₂g
a = m₂g / (m₁ + m₂)
a = (10 kg * 9.8 m/s²) / (10 kg + 5 kg) = 6.53 m/s²
Both objects have an acceleration of 6.53 m/s²
