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MaRussiya [10]
3 years ago
11

Liquid A decomposes with nth-order kinetics in a batch reactor A->B, r =kca. the conversion of A reaches 50% in a five minute

run.
a. What is the order of the reaction if it takes 10 minutes to reach 75% conversion?
b. What is the order of the reaction if it takes 20 minutes to reach 75% conversion?
c. What is the order of the reaction if it takes 30 minutes to reach 75% conversion?
Chemistry
1 answer:
Cloud [144]3 years ago
8 0

Answer:

A) 1

B) 2.5

C) 3.32

Explanation:

The  possibility of n=1 is not achievable in 20 minutes and 30 minutes as calculated n=1 for 10 minutes. The same conversion cannot be achieved for the  rest of the time which is impossible as 75% conversion and it cannot   be achieved at 10 min and 20 min at the same time

A) what is the order of the reaction if it takes 10 minutes to reach 75% conversion

= n ( order )  = 1

B) what is the order of reaction if it takes 20 minutes to reach 75% conversion

= n ( order ) ≈ 2.5

C) what is the order of reaction if it takes 30 minutes to reach 75% conversion

= n ( order ) ≈ 3.32

attached below is a detailed solution

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A) 54.04%

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Explanation:

A) From the problem we have

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<em>2)</em> Vg + Vs = 0.675 cm³

Where M stands for mass, V stands for volume, and g and s stand for gold and silver respectively.

We can rewrite the first equation using the density values:

<em>3)</em> Vg * 19.3 g/cm³ + Vs * 10.5 g/cm³ = 9.40

So now we have<em> a system of two equations</em> (2 and 3) <em>with two unknowns</em>:

We <u>express Vg in terms of Vs</u>:

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  • Vg = 0.675 - Vs

We <u>replace the value of Vg in equation 3</u>:

  • Vg * 19.3 + Vs * 10.5 = 9.40
  • (0.675-Vs) * 19.3 + Vs * 10.5 = 9.40
  • 13.0275 - 19.3Vs + 10.5Vs = 9.40
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Now we <u>calculate Vg</u>:

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We <u>calculate Mg from Vg</u>:

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We calculate the mass percentage of gold:

  • 5.08 / 9.40 * 100% = 54.04%

B)

We multiply 24 by the percentage fraction:

  • 24 * 54.04/100 = 12.97-karat ≅ 13-karat
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