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Harrizon [31]
3 years ago
15

Consider two bonds, A and B. Both bonds presently are selling at their par value of $1,000. Each pays interest of $120 annually.

Bond A will mature in five years, while bond B will mature in eight years. If the yields to maturity on the two bonds change from 12% to 10%
a. Both bonds will decrease in value but bond B will decrease more than bond A
b. Both bonds will increase in value but bond B will increase more than bond A
c. Bond A will increase in value, but Bond B will decrease in value.
d. Both bonds will increase in value but bond B will increase more than bond A
e. Both bonds will increase in value but bond A will increase more than bond B
Chemistry
1 answer:
Dima020 [189]3 years ago
6 0

Answer:

The answer is "Option b"

Explanation:

The longer its maturity, therefore higher the rise in prices as the interest rate changes, therefore higher the value from both bonds, but bond B is greater than bond A.

 

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3 years ago
For the reaction H2PO4- HAsO4 2-HPO4 2-+H2AsO4- <br> what species are a conjugate acid-base pair?
aleksklad [387]

Ionic equation:

\text{H}_2\text{PO}_4^{-} + \text{HAsO}_4^{2-} \to \text{HPO}_4^{2-} + \text{H}_2\text{AsO}_4^{-}

The acid and base in a conjugate pair differ by only one proton \text{H}^{+}. The acid loses one proton to produce a conjugate base, whereas the base gains a proton to produce its conjugate acid.

\text{H}_2\text{PO}_4^{-} loses one proton to produce \text{HPO}_4^{2-} in this reaction.

\text{H}_2\text{PO}_4^{-} \to \text{H}^{+} + \text{HPO}_4^{2-}

Meanwhile, \text{HAsO}_4^{2-} gains one proton to form \text{H}_2\text{AsO}_4^{-}.

\text{HAsO}_4^{2-} + \text{H}^{+} \to \text{H}_2\text{AsO}_4^{-}

Therefore

  • \text{H}_2\text{PO}_4^{-} is the conjugate acid  \text{HPO}_4^{2-}, its conjugate base.
  • \text{HAsO}_4^{2-} is the conjugate base of \text{H}_2\text{AsO}_4^{-}, its conjugate acid.
8 0
3 years ago
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What belief do Deists hold about the universe?
liubo4ka [24]
"<span>b. God had created a mechanistic universe that could only be understood through the Bible" is the best option since Deists believe God treats the universe in a "hands off" way. </span>
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3 years ago
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A 100.0 mL sample of 0.300 M NaOH is mixed with a 100.0 mL sample of 0.300 M HNO3 in a coffee cup calorimeter. If both solutions
Mars2501 [29]

Answer:

Qm  = -55.8Kj/mole

Explanation:

NaOH(aq) + HNO₃(aq) => NaNO₃(aq) + H₂O(l)

Qm = (mc∆T)water /moles acid

Given => 100ml(0.300M) NaOH(aq) + 100ml(0.300M)HNO₃(aq)

=> 0.03mole NaOH(aq) + 0.03mole HNO₃(aq)

=> 0.03mole NaNO₃(aq) + 0.03mole H₂O(l)

ΔH⁰rxn = [(200ml)(1.00cal/g∙°C)(37 – 35)°C]water / 0.03mole HNO₃

= 13,333 cal/mole x 4.184J/cal = 55,787J/mol = 55.8Kj/mole (exothermic)*

Heat of reactions comes from formation of H-Oxy bonds on formation of water of reaction and heats the 200ml of solvent water from 35⁰C to 37⁰C.

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