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Harrizon [31]
3 years ago
15

Consider two bonds, A and B. Both bonds presently are selling at their par value of $1,000. Each pays interest of $120 annually.

Bond A will mature in five years, while bond B will mature in eight years. If the yields to maturity on the two bonds change from 12% to 10%
a. Both bonds will decrease in value but bond B will decrease more than bond A
b. Both bonds will increase in value but bond B will increase more than bond A
c. Bond A will increase in value, but Bond B will decrease in value.
d. Both bonds will increase in value but bond B will increase more than bond A
e. Both bonds will increase in value but bond A will increase more than bond B
Chemistry
1 answer:
Dima020 [189]3 years ago
6 0

Answer:

The answer is "Option b"

Explanation:

The longer its maturity, therefore higher the rise in prices as the interest rate changes, therefore higher the value from both bonds, but bond B is greater than bond A.

 

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A solution containing 60 grams of nano3 completely dissolved in 50. Grams of water at 50°c is classified as being
Igoryamba

Answer:

<em>A solution containing 60 grams of nano3 completely dissolved in 50. Grams of water at 50°c is classified as being</em> <u>supersaturaded</u>

Explanation:

This question is about solubility.

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  • Saturated: the concentration is the maximum permitted at the given temperature, under normal conditions.

  • Supersaturated: the concentration has overcome the maximum permitted at the given temperature. This is possible only under special conditions and is a very unstable state.

Each substance has its own, unique solubility properties. So, in order to tell the state of the solution you need to compare with either solubility tables, or solubility curves; or run you own experiments.

  • In internet you can find the solubility curve of NaNO₃ showing the solubility for a wide range of temperatures.

  • In such curve the solubility of NaNO₃ at 50°C is about 115 g of NaNO₃ per 100 g  of water.

  • Hence, do the proportion to determine the amount of solute that can be dissolved in 50 grams of water at 50°CÑ

       115 g NaNO₃ / 100 g H₂O = x / 50 g H₂O  ⇒ x =  57.5 g NaNO₃

  • <u>Conclusion</u>: 50 grams of water can contain 57.5 g of NaNO₃ dissolved; so, <em>a solution containing 60 g of NaNO₃ completely dissolved in 50 grams of water is supersaturated.</em>

<em />

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