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Serjik [45]
4 years ago
12

How many moles of bromine (Br) atoms are in a sample of 2.03 × 1024 atoms?

Chemistry
2 answers:
ki77a [65]4 years ago
5 0

<u>Answer:</u> The number of moles of bromine atoms in the given amount of sample is 3.37 moles.

<u>Explanation:</u>

According to mole concept:

1 mole of an element contains 6.022]times 10^{23} number of atoms

We are given:

Number of bromine atoms = 2.03\times 10^{24}

As, 6.022]times 10^{23} atoms form 1 mole of an element.

So, 2.03\times 10^{24} atoms will form = \frac{1}{6.022\times 10^{23}}\times 2.03\times 10^{24}=3.37moles of bromine element.

Hence, the number of moles of bromine atoms in the given amount of sample is 3.37 moles.

andriy [413]4 years ago
3 0

The mole is simply an Avogadros number of anything( in this case Br atoms)

The Avogadro number is 6.022 x 10^23.

So no of moles = No of atoms / 6.022 x 10^23 = 2.03 x 10^24 / 6.022 x 10^23 = 3.37 Moles.
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The absorbance of an equilibrium mixture containing FeSCN2 was measured at 447 nm and found to be 0.347. What is the equilibrium
Ksenya-84 [330]

Answer:

The concentration is C = 1.11 mol/L

Explanation:

From the question we are told that

     The absorbance is  A = 0.347

       The length is  l =  447 nm  =  447 *10^{-7} \ cm

     

Generally absorbance is mathematically represented as

        A =  \epsilon*  C * l

where \epsilon is the molar absorptivity of  FeSCN2  with a value \epsilon  =  7.0*10^3 L/cm/mol

 and  C is the equilibrium concentration of FeSCN2

So  

       C = \frac{A}{\epsilon *  l  }

substituting values

        C = \frac{0.347}{7.0*10^{3} *  447 *10^{-7}  }

         C = 1.11 mol/L

5 0
3 years ago
Use the law of conservation of mass to answer the questions. Consider a hypothetical reaction in which A and B are reactants and
shutvik [7]

Answer:

26 grams of D will be produced.

Explanation:

The reaction is given by:

A + B ----->  C + D

Mass of A reacted = 21 g

Mass of B reacted = 22 g

Mass of C formed = 17 g

Mass of D formed = m =?

According to law of conservation of mass, the total mass of the reactants used is equal to the total mass of the product formed.

Then:

mass of A reacted + mass of B reacted = mass of C formed + mass of D formed

21 + 22 = 17 + m

m = 26 g

5 0
4 years ago
Plz help me guys<br><br> A<br><br> B<br><br> C<br><br> D
Taya2010 [7]

Answer:

C

Explanation:

I think

3 0
4 years ago
A solution made by mixing 20.0 g of a non-volatile compound with 125 mL of water at 25°C has a vapor pressure of 22.67 torr. Wha
Ainat [17]

We have that the molecular weight (3sf) of the compound (g/mol)

m=44.15g/mol

From the question we are told

A solution made by mixing 20.0 g of a non-volatile compound with 125 mL of water at 25°C has a vapor pressure of 22.67 torr. What is the molecular weight (3sf) of the compound (g/mol).

Generally the equation for the Rouault's law is mathematically given as

P=P_0 N

22.67=23.8*\frac{\frac{12.5}{18}}{\frac{125}{18}+\frac{15}{m}}\\\\\6.95+\frac{15}{m}=7.29\\\\\frac{15}{m}=7.29-6.95\\\\m=\frac{15}{0.34}\\\\m=44.11g/mol

Therefore

The molecular weight (3sf) of the compound (g/mol)

m=44.15g/mol

For more information on this visit

brainly.com/question/17756498

4 0
3 years ago
Choose all of the options that demonstrate how humans are impacting the water cycle.
Fantom [35]

Answer:

A.) Air pollutants wash onto land and water bodies from precipitation

C.) Storm water runoff carries pollution

I hope I helped! ^-^

5 0
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