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Tanzania [10]
3 years ago
15

Explain the conditions in which a person can or can’t hear a echo

Physics
2 answers:
victus00 [196]3 years ago
6 0

Answer:

Explained

Explanation:

The necessary condition for an echo to occur are

1) The distance between the sound source and the object of reflection must be equal to or greater than 17 meters.

2) the time period between hearing the original sound and the echo must not be less than 0.1 second, because human ear is not that sensitive to distinguish between two sounds within a gap of time less than 0.1 second.

Olenka [21]3 years ago
5 0

When your in the mountains or in a quiet room

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A 1.60 m cylindrical rod of diameter 0.550 cm is connected to a power supply that maintains a constant potential difference of 1
bija089 [108]

1.

Answer:

Part a)

\rho = 1.35 \times 10^{-5}

Part b)

\alpha = 1.12 \times 10^{-3}

Explanation:

Part a)

Length of the rod is 1.60 m

diameter = 0.550 cm

now if the current in the ammeter is given as

i = 18.7 A

V = 17.0 volts

now we will have

V = I R

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now we know that

R = \rho \frac{L}{A}

0.91 = \rho \frac{1.60}{\pi(0.275\times 10^{-2})^2}

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Part b)

Now at higher temperature we have

V = I R

17.0 = 17.3 R

R = 0.98 ohm

now we know that

R = \rho \frac{L}{A}

0.98 = \rho' \frac{1.60}{\pi(0.275\times 10^{-2})^2}

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2.

Answer:

Part a)

i = 1.55 A

Part b)

v_d = 1.4 \times 10^{-4} m/s

Explanation:

Part a)

As we know that current density is defined as

j = \frac{i}{A}

now we have

i = jA

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j = 1.90 \times 10^6 A/m^2

A = \pi(\frac{1.02 \times 10^{-3}}{2})^2

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i = 1.55 A

Part b)

now we have

j = nev_d

so we have

n = 8.5 \times 10^{28}

e = 1.6 \times 10^{-19} C

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v_d = 1.4 \times 10^{-4} m/s

8 0
3 years ago
slader Question: A Model Rocket Is Launched Straight Upward With An Initial Speed Of 50m/s. Iit Accelerates With A Constant Upwa
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Answer:

Maximum height reached by the rocket is

y_{max} = 308 m

total time of the motion of rocket is given as

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t_1 = 2.84 s

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-150 = 55.68 t - \frac{1}{2}(9.81) t^2

t_2 = 13.6 s

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T = 13.6 + 2.84 = 16.44 s

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