An engineer is applying dimensional analysis to study the flow of air through this horizontal sudden contraction for the purpose
1 answer:
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Answer:
Explanation:
Approximately, we can use the ideal gas law, below we see how we can deduce the density from general gas equation. To do this, remember that the number of moles n is equal to , where m is the mass and M the molar mass of the gas, and the density is
.
For air and
So,
Answer:
1st value = 1.828 * 10 ^9 gm/m^2 ------- 10th value = 7.312 * 10^9 gm/m^2
Explanation:
initial load ( Wp) = 200 g
W1 ( value by which load values increase ) = 100 g
Ten different beam loading values :
Wp + w1 = 300g ----- p1
Wp + 2W1 = 400g ---- p2
Wp + 3W1 = 500g ----- p3 ----------------- Wp + 10W1 = 1200g ---- p10
x = 10.25" = 0.26 m
b = 1.0" = 0.0254 m
t = 0.125" = 3.175 * 10^-3 m
using the following value to determine the load values at different beam loading values
attached below is the remaining part fo the solution
