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anyanavicka [17]
2 years ago
7

An engineer is applying dimensional analysis to study the flow of air through this horizontal sudden contraction for the purpose

of characterizing the pressure drop. The flow is being modeled as constant density and steady. What is the functional relationship of the variables that characterize this situation
Engineering
1 answer:
navik [9.2K]2 years ago
4 0

Answer:

The answer is " \Delta p = f(V1, p, V2, d, D, L)"

Explanation:

Please find the complete question in the attached file.

Its change in temperature in pipes depends on rate heads and loss in pipes owing to pipe flow, contractual loss, etc.

The temperature change thus relies on V1 v2 p d D L.

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Answer:

The solution code is written in Python:

  1. items = [{"id": 37697, "code": ""},{"id": 37698, "code": ""},{"id": 37699, "code": ""},{"id": 37699, "code": ""}, {"id": 37699, "code": ""},
  2. {"id": 37699, "code": ""},{"id": 37699, "code": ""},{"id": 37699, "code": ""},{"id": 37700, "code": ""} ]
  3. items[0]["code"] = 1
  4. for i in range(1, len(items)):
  5.    if(items[i]["id"] == items[i-1]["id"]):
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  7.    else:
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  9. print(items)

Explanation:

Firstly, let's create a list of dictionary objects. Each object holds an id and a code (Line 1-2). Please note all the code is initialized with zero at the first beginning.

Next, we can assign 1 to the <em>code</em> property of items[0] (Line 4).

Next, we traverse through the items list started from the second element (Line 6). We set an if condition to check if the current item's id is equal to the previous item (Line 7). If so, we assign the previous item's code + 1 to the current item's code (Line 8). If not, we assign 1 to the current item's code (Line 10).

At last, we print out the item (Line 12) and we shall get

[{'id': 37697, 'code': 1}, {'id': 37698, 'code': 1}, {'id': 37699, 'code': 1}, {'id': 37699, 'code': 2}, {'id': 37699, 'code': 3}, {'id': 37699, 'code': 4}, {'id': 37699, 'code': 5}, {'id': 37699, 'code': 6}, {'id': 37700, 'code': 1}]

 

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