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larisa86 [58]
3 years ago
10

Explain why a sound becomes louder as you move closer to the source of the sound.​

Physics
1 answer:
Marizza181 [45]3 years ago
6 0

Answer:

The wavelength of frequency of the sound are closer to each other

Or

The frequency of the sound increases as it moves towards you

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A bridge that was 5.0 m long has been washed out by the rain several days ago. How fast must a car be going to successfully jump
amid [387]

Answer:

Speed, v = 7.83 m/s

Explanation:

It is given that,

Length of the bridge, l = 5 m

The road on the far side is 2.0 m lower than the road on this side, x = 2 m

The horizontal distance covered by the car is 5 meters and the vertical distance covered by the car is 2 meters.

Initial speed of the car, u = 0

Let t is the time taken by the car . Using the second equation of motion as :

For vertical distance :

s=ut+\dfrac{1}{2}gt^2

t=\sqrt{\dfrac{2\times 2}{9.8}}=0.638\ s

Let v is the velocity to jump the stream. It is given by :

Horizontal distance, d = 5 m

v=\dfrac{5\ m}{0.638\ s}

v = 7.83 m/s

So, the car should travel with a speed of 7.83 m/s. Hence, this is the required solution.

8 0
4 years ago
calcular la longitud de un péndulo que oscila a 10 Hz en santa fe de bogota, sabiendo que en esta ciudad la aceleracion de la gr
cricket20 [7]

Answer:

L=2.48*10^{-3} m

Explanation:

The period equation for a pendulum is given by:

T=2\pi \sqrt{\frac{L}{g}}

and we know that T = 1/f, where f is the frequency, so we will have:

\frac{1}{f}=2\pi \sqrt{\frac{L}{g}}

Now, we just need to solve this equation for L.

\frac{1}{2\pi f}=\sqrt{\frac{L}{g}}

L=\frac{g}{(2\pi f)^{2}}

  • g is the gravity in Bogota (g=9.78 m/s^{2})
  • f is 10 Hz
  • L is the lenght of the pendulum

L=\frac{9.78}{(2\pi*10)^{2}}

L=2.48*10^{-3} m

I hope it helps you!

5 0
3 years ago
How much work is required to lift 40 N 1.5 M
LiRa [457]

Answer: 200 joules I think.

Explanation:

3 0
3 years ago
What do you do if you approach a railroad crossing with a crossbuck sign that has no lights or gates
miv72 [106K]
Proceed with caution before crossing
3 0
4 years ago
A catalyst decreases the activation energy of a particular exothermic reaction by 47 kJ/mol, to 33 kJ/mol. Assuming that the mec
Svetlanka [38]

Answer:

Activation energy for catalysed reaction =33kJ/mol.

Products are 59kJ lower in energy than the reactants.

4 0
3 years ago
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