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2 years ago

I really need help please help me :(

Chemistry

2 answers:

shutvik [7]2 years ago

6 0

Answer:

fiugure out what the lettes stand for

Explanation:

brilliants [131]2 years ago

3 0

Do it on your own and stop asking help for everything

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inessss [21]

I need help with this too:(( did u get it?

6 0

2 years ago

A 37.2 g sample of copper at 99.8 °C is carefully placed into an insulated container containing 188 g of water at 18.5 °C. Calcu

klasskru [66]

Answer:

T₂ = 19.95°C

Explanation:

From the law of conservation of energy:

$Heat\ Lost\ by\ Copper = Heat\ Gained\ by\ Water\\m_cC_c\Delta T_c = m_wC_w\Delta T_w$

where,

mc = mass of copper = 37.2 g

Cc = specific heat of copper = 0.385 J/g.°C

mw = mass of water = 188 g

Cw = specific heat of water = 4.184 J/g.°C

ΔTc = Change in temperature of copper = 99.8°C - T₂

ΔTw = Change in temperature of water = T₂ - 18.5°C

T₂ = Final Temperature at Equilibrium = ?

Therefore,

$(37.2\ g)(0.385\ J/g.^oC)(99.8\ ^oC-T_2)=(188\ g)(4.184\ J/g.^oC)(T_2-18.5\ ^oC)\\99.8\ ^oC-T_2 = \frac{(188\ g)(4.184\ J/g.^oC)}{(37.2\ g)(0.385\ J/g.^oC)}(T_2-18.5\ ^oC)\\\\99.8\ ^oC-T_2 = (54.92) (T_2-18.5\ ^oC)\\54.92T_2+T_2 = 99.8\ ^oC + 1016.02\ ^oC\\\\T_2 = \frac{1115.82\ ^oC}{55.92}$

T₂ = 19.95°C

6 0

2 years ago

The kilocalories in one can of cola if it has 40. g of carbohydrate and no fat or protein

Marysya12 [62]

Answer:

One can of cola contain 0.16 kcal of carbohydrates.

Explanation:

Given data:

mass of cola can = 40 g

kilocalories of carbohydrates = ?

Solution:

we know that there are 4 cal of carbohydrates per gram.

40 g × 4 cal/g = 160 cal

Now we will convert calories into kilocalories. There are 1000 calories in one kilocalories so,

160/1000 = 0.16 kcal

so, one can of cola contain 0.16 kcal of carbohydrates.

6 0

2 years ago

The percent composition of all elements in HClO3 is:

ser-zykov [4K]

The answer is b. 1% H, 42% Cl, 57% O.

Let's first calculate a molar mass (M) of HClO₃. Molar mass is a mass of 1 mole of a substance. It can be expressed as the sum of relative atomic masses (Ar), which are masses of atoms of the elements:
M(HClO₃) = Ar(H) + Ar(Cl) + 3Ar(O)

Ar(H) = 1 u
Ar(Cl) = 35.5 u
Ar(O) = 16 u
M(HClO₃) = Ar(H) + Ar(Cl) + 3Ar(O) = 1 + 35.5 + 3 · 16 = 84.5 u

Now, we just need to calculate mass percent of each element using the proportion:
Ar : x = M : 100% ⇒ x = Ar ÷ M · 100%

Hydrogen: x = Ar(H) ÷ M · 100% = 1 ÷ 84.5 · 100% = 1.2% ≈ 1%
Chlorine: x = Ar(Cl) ÷ M · 100% = 35.5 ÷ 84.5 · 100% = 42%
Oxygen: x = 3Ar(O) ÷ M · 100% = 48 ÷ 84.5 · 100% = 56.8% ≈ 57%

6 0

3 years ago

The substance used for decolorization of undisireable color in a crystalline substance is

kvv77 [185]

The substance used for decolorization of undesirable color in a crystalline substance is powdered animal charcoal

Decolorization is the process of eliminating organic contaminants with vivid colors from the sample mixture.

Unwanted colors are removed by boiling the item with a suitable amount of powdered animal charcoal in a hot solution that has been filtered so that the charcoal may absorb the colors. The charcoal is a finely divided carbon.

Learn more about decolorization -

brainly.com/question/23009718

#SPJ4

3 0

1 year ago