Answer:
-2.70 rad/s²
Explanation:
Given that
ω1 = initial angular velocity of the flywheel, which is 6.77 rev/s
If we convert it to rad/s, we have
(6.77 x 2π) rad/s = 13.54π rad/s
ω2 = final angular velocity of the flywheel = -3.51 rev/s,
On converting to rad/s also, we have
(-3.51 x 2π) rad/s = 7.02π rad/s
α = average angular acceleration of the flywheel = ?
Δt = elapsed time = 23.9 s
Now, using the formula, α = (ω2 - ω1)/Δt. On substituting, we have
α = (-7.02π rad/s - 13.54π rad/s)/23.9 s
α = -20.56π rad/s / 23.9 s
α = -64.59 rad/s / 23.9 s
α = -2.70 rad/s²
Therefore, the average angular acceleration of the flywheel is -2.70 rad/s²
