What is the acceleration of a 5kg mass pushed by a 10N force?
1 answer:
You might be interested in
Answer:
∑ τ =0, L₀ =
Explanation:
In a circular turning movement, when the arms are extended and then contracted in two possibilities:
- They are lowered the force of gravity is what pulls them, the tension of the muscle becomes zero to allow this movement.
In this movement the force is vertical(gravity) and the movement of the center of mass of each arm is vertical, so that the work is the weight value of the arm by the distance traveled by the center of mass.
- Another possibility is that the arms have stuck to the body, in this case the person's muscles perform the force, this force is horizontal and the displacement is the horizontal of the center of mass of the arms from the extended position to the contracted
In these movements the torque of the external force is equal for each arm, but in the opposite direction, so they are canceled where a net torque of zero, this causes the angular momentum to be preserved, which changes is the moment of inertia of the system and therefore you must also change the angular velocity to keep your product constant
∑ τ =0
L₀ =
I₀ w₀ = I w
Answer:
a).β=0.53 T
a).β=0.40 T
Explanation:
The magnetic field at distance 'r' from the center of toroid is given by:
a).
b).
The distance is the radius add the cross section so:
Answer:
Distance traveled during this acceleration will be 6950 m
Explanation:
Wear have given maximum speed tat will be equal to final speed of the car v = 278 m/sec
Constant acceleration
As the car starts initially starts from rest so initial velocity of the car u = 0 m/sec
From third equation of motion
Putting all values in equation
s = 6950 m
So distance traveled during this acceleration will be 6950 m