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kakasveta [241]

2 years ago

6

A certain skin lotion is a fine mixture of water and various oils. This lotion is cloudy and cannot be separated into oil and wa

ter by filtration. Moreover, its components do not separate when left standing. What type of mixture is it? solution suspension colloid compound NextReset

2 answers:

timofeeve [1]2 years ago

6 0

The answer you are looking for would be a colliod. Hope this helps have a great day!!

irinina [24]2 years ago

4 0

The answer is: colloid.

In the presence of an emulsifying agent, a mixture of oil and water becomes a colloidal dispersion.

Colloidal dispersion (colloid) is a system, in which discrete particles, droplets or bubbles of a dispersed phase (in this case oil), whose size at least in one dimension is in the range from 1 to 1000 nm are distributed in the other, usually continuous phase - dispersion medium (in this case water) differing from the dispersed phase in composition or state of aggregation.

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2 years ago

Read 2 more answers

The question is in the picture below

Rus_ich [418]

Answer:

$\Delta\text{H}_1+2\Delta\text{H}_2-\Delta\text{H}_3$

Explanation:

Hess's Law of Constant Heat Summation states that if a chemical equation can be written as the sum of several other chemical equations, the enthalpy change of the first chemical equation is equal to the sum of the enthalpy changes of the other chemical equations. Thus, the reaction that involves the conversion of reactant A to B, for example, has the same enthalpy change even if you convert A to C, before converting it to B. Regardless of how many steps it takes for the reactant to be converted to the product, the enthalpy change of the overall reaction is constant.

With Hess's Law in mind, let's see how A can be converted to 2C +E.

$\bf{\text{A} \rightarrow 2\text{B}}$ (Δ $\text{H}_1$ ) -----(1)

Since we have 2B, multiply the whole of II. by 2:

$\bf{2\text{B} \rightarrow 2\text{C} +2\text{D}}$ (2Δ $\text{H}_2$ ) -----(2)

This step converts all the B intermediates to 2C +2D. This means that the overall reaction at this stage is $\text{A} \rightarrow 2\text{C} +2\text{D}$ .

Reversing III. gives us a negative enthalpy change as such:

$\bf{2\text{D} \rightarrow \text{E}}$ (-Δ $\text{H}_3$ ) -----(3)

This step converts all the D intermediates formed from step (2) to E. This results in the overall equation of $\text{A} \rightarrow 2\text{C} +\text{E}$ , which is also the equation of interest.

Adding all three together:

$\text{A} \rightarrow 2\text{C}+\text{E}$ ( $\bf{\Delta\text{H}_1+2\Delta\text{H}_2-\Delta\text{H}_3 }$ )

Thus, the first option is the correct answer.

Supplementary:

To learn more about Hess's Law, do check out: brainly.com/question/26491956

4 0

1 year ago

The following equation is an example of a ______________ reaction. 2 NaCl + F2 → 2 NaF + Cl2 ???

olga55 [171]

Answer:

double replacement is the answer

3 0

2 years ago

How much heat is required to convert 20.0 g of ice at 50.0⁰C to liquid water at 0.0⁰C? The specific heat of ice is 2.06 J/(g∙⁰C)

Alex777 [14]

Answer:

8740 joules are required to convert 20 grams of ice to liquid water.

Explanation:

The amount of heat required ( $Q$ ), measured in joules, to convert ice at -50.0 ºC to liquid water at 0.0 ºC is the sum of sensible heat associated with ice and latent heat of fussion. That is:

$Q = m\cdot [c\cdot (T_{f}-T_{o})+L_{f}]$ (1)

Where:

$m$ - Mass, measured in grams.

$c$ - Specific heat of ice, measured in joules per gram-degree Celsius.

$T_{o}$ , $T_{f}$ - Temperature, measured in degrees Celsius.

$L_{f}$ - Latent heat of fussion, measured in joules per gram.

If we know that $m = 20\,g$ , $c = 2.06\,\frac{J}{g\cdot ^{\circ}C}$ , $T_{f} = 0\,^{\circ}C$ , $T_{o} = -50\,^{\circ}C$ and $L_{f} = 334\,\frac{J}{g }$ , then the amount of heat is:

$Q = (20\,g)\cdot \left\{\left(2.06\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot [0\,^{\circ}C-(-50\,^{\circ}C)]+334\,\frac{J}{g} \right\}$

$Q = 8740\,J$

8740 joules are required to convert 20 grams of ice to liquid water.

3 0

2 years ago