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iragen [17]
3 years ago
15

How much heat is released when 1.4 mol of hydrogen fluoride are produced? H2(g) +F2(g) → 2HF(g) +536kJ (Please show work)

Chemistry
1 answer:
polet [3.4K]3 years ago
7 0

Answer:

375.2 kJ

Explanation:

  • H₂(g) +F₂(g) → 2HF(g) +536kJ

The information the equation above provides lets us know that when 2 mol of hydrogen fluoride (HF) are produced, 536 kJ of energy (as heat) is produced.

We can then <u>state a rule of three</u>:

  • 2 mol HF --------  536 kJ
  • 1.4 mol HF --------- X

And <u>solve for X</u>:

  • X = 1.4 mol * 536 kJ / 2 mol
  • X = 375.2 kJ
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  • Valence Shell Electron Pair Repulsion theory is commonly known as VSEPR theory and it helps to predict the geometry of molecules.
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Thus, the valence electrons in SF_{6} are-

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  • The Lewis structure of SF_{6} is - (Image attached).
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  • Molecular geometry us also octahedral with bond angles 90°.
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To learn more about Lewis structures visit:

brainly.com/question/12307841?referrer=searchResults

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