How much heat is released when 1.4 mol of hydrogen fluoride are produced? H2(g) +F2(g) → 2HF(g) +536kJ (Please show work)

Chemistry

1 answer:

polet [3.4K]2 years ago

7 0

Answer:

375.2 kJ

Explanation:

H₂(g) +F₂(g) → 2HF(g) +536kJ

The information the equation above provides lets us know that when 2 mol of hydrogen fluoride (HF) are produced, 536 kJ of energy (as heat) is produced.

We can then state a rule of three:

2 mol HF -------- 536 kJ

1.4 mol HF --------- X

And solve for X:

X = 1.4 mol * 536 kJ / 2 mol

X = 375.2 kJ

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