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Blizzard [7]
3 years ago
5

Approximately how much matter is there in the sun?

Physics
1 answer:
andrew11 [14]3 years ago
7 0
<span>1.989 Ă— 10^30 kg The sun consists of about 70% hydrogen, 28% helium, 1.5% carbon, nitrogen and oxygen, and 0.5% all other elements. Additionally, the sun's mass is decreasing every second as it fuses 610 million metric tons of hydrogen into 606 million metric tons of helium each second for a loss of 4 million metric tons per second.</span>
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When is it easiest for a person to build up static electricity?
Elena-2011 [213]
Idkk look it up on quizlet, they flash cards to tell you lots of stuff
3 0
4 years ago
A potential difference V = 100 V is applied across a capacitor arrangement with capacitances C1 = 10.0 mF, C2 = 5.00 mF, and C3
Gala2k [10]

Given Information:

Potential difference = V = 100 V

Capacitance C₁ = 10 mF

Capacitance C₂ = 5 mF

Capacitance C₃ = 4 mF

Required Information:

a. Charge q₃

b. Potential difference V₃

c. Stored energy U₃

d. Charge q ₁

e. Potential difference V₁

f. Stored energy U₁

g. Charge q  ₂

h. Potential difference V₂  

i. Stored energy U₂

Answer:

a. Charge q₃ = 0.4 C

b. Potential difference V₃  = 100 V

c. Stored energy  U₃  = 20 J

d. Charge q ₁  = 0.33 C

e. Potential difference  V₁  = 33 V

f. Stored energy U₁  = 5.445 J

g. Charge q  ₂ = 0.33 C

h. Potential difference V₂  = 66 V

i. Stored energy U₂ = 10.89 J

Explanation:

Please refer to the circuit attached in the diagram

a. Charge q₃

As we know charge in a capacitor is given by

q₃ = C₃V₃

q₃ = 4x10⁻³*100

q₃ = 0.4 C

b. Potential difference V₃

The potential difference V₃  is same as V

V₃  = 100 V

c. Stored energy U₃

Energy stored in a capacitor is given by  

U₃  = ½C₃V₃²

U₃  = ½*4x10⁻³*100²

U₃  = 20 J

d. Charge q ₁

Since capacitor C₁ and C₂ are in series their equivalent capacitance is

Ceq = C₁*C₂/C₁ + C₂

Ceq = 10x10⁻³*5x10⁻³/10x10⁻³ + 5x10⁻³

Ceq = 3.33x10⁻³ F

q ₁ = Ceq*V

q ₁ = 3.33x10⁻³*100

q ₁ = 0.33 C

e. Potential difference V₁

V₁  = q ₁/C₁

V₁  = 0.33/10x10⁻³

V₁  = 33 V

f. Stored energy U₁

U₁  = ½C₁V₁²

U₁  = ½*10x10⁻³*(33)²

U₁  = 5.445 J

g. Charge q  ₂

q₂ = Ceq*V

q₂ = 3.33x10⁻³*100

q₂ = 0.33 C

h. Potential difference V₂  

V₂  = q ₂/C₂

V₂  = 0.33/5x10⁻³

V₂  = 66 V

i. Stored energy U₂

U₂ = ½C₂V₂²

U₂ = ½*5x10⁻³*(66)²

U₂ = 10.89 J

8 0
4 years ago
What type of relationship exists between momentum and mass?
alina1380 [7]

Answer:

A. Direct

Explanation:

Thats just how it be

4 0
3 years ago
Q7) A box sliding with a velocity of 5 m/s accelerates at 2 m/s^2. How
grigory [225]

Answer:

The box displacement after 6 seconds is 66 meters.

Explanation:

Let suppose that velocity given in statement represents the initial velocity of the box and, likewise, the box accelerates at constant rate. Then, the displacement of the object (\Delta s), in meters, can be determined by the following expression:

\Delta s = v_{o}\cdot t+\frac{1}{2}\cdot a\cdot t^{2} (1)

Where:

v_{o} - Initial velocity, in meters per second.

t - Time, in seconds.

a - Acceleration, in meters per square second.

If we know that v_{o} = 5\,\frac{m}{s}, t = 6\,s and a = 2\,\frac{m}{s^{2}}, then the box displacement after 6 seconds is:

\Delta s = 66\,m

The box displacement after 6 seconds is 66 meters.

5 0
3 years ago
In which environment might you expect a deposit of rock salt or sock gypsum to have formed?
wolverine [178]
Most likely in a shallow sea environment. 
8 0
3 years ago
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