Answer:
speed
Explanation:
according to your question, your answer is speed
So based on your question where there is a block of mass m1= 8.8kg in the inclined plane with an angle of 41 with respect to the horizontal. To find the spring constant of the problem were their is a coefficients of friction of 0.39 and 0.429, you must use the formula K*x^2=m*a*sin(angle). By calculating the minimum spring constant is 220.66 N/m^2
Answer:
Explanation:
Relative to an origin at the bottom of the hill,
PE = mgh = 10(9.8)(15) = 1470 J
Answer:
132 N
Explanation:
newton's second law states that force = mass * acceleration
F = ma
plug in 66 kg for mass and 2 m/s^2 for acceleration
F = 66 * 2
F = 132 N