Answer:
I have two methods to distinguish between concentrated and dilute nitric acid
Method 1: Using magnesium/manganese.
Mg + 2HNO₃ (1%) → Mg(NO₃) + H₂
very very dilute
Mg + 4HNO₃ → Mg(NO₃)+ 2H₂O +2NO₂
concentrated
In the first reaction of magnesium with concentrated nitric acid, hydrogen is evolved.
In the second reaction of magnesium with very very dilute nitric acid, water is evolved.
Using the respective tests for hydrogen and water, we can test them.
Method 2: Using iron.
3 Fe + 8HNO₃→ 3Fe(NO₃)₂ + 4H₂O + 2NO
dilute
Fe + 6HNO₃→ Fe(NO₃)₃ + 3H₂O + 3NO₂
concentrated
In the first case of method 2,
Fe(NO₃)₂ ⇆ Fe²⁺ + (NO₃) ⁻ Iron with valency 2+ is formed
In the second case of method 2,
Fe(NO₃)₃ ⇄ Fe³⁺ + (NO₃) ⁻ Iron with valency 3+ is formed
Brainlist pls!
Explanation:
Phases of Matter
Question Answer
Vaporization that occurs at and below the surface of a liquid boiling
A solid that is made up of crystals in which particles are arranged in a regular, repeating pattern crystalline solid
A solid made up of particles that are not arranged in a regular pattern amorphous solid
Answer:
The balanced equation is :
NH4NO2(solid) = N2(gas) + 2 H2O(liquid)
Explanation:
A balanced chemical equation is an equation that has an equal number of atoms and charges on both sides of the equation. The given equation in question is imbalanced as the number of atoms not equal.
In this reaction, solid ammonium nitrite breaks into nitrogen gas and water, reaction known as decomposition.
The correct and balanced equation as follows :
NH4NO2(s) = N2(g) + 2 H2O(l)
Answer:
Explanation:
In this case, we have to start with the <u>reagents</u>:
The compounds given by the problem are:
-) <u>Nitrogen gas</u> =
-) <u>Water vapor</u> =
-) <u>Aluminum oxide</u> =
Now, we can put the products in the <u>reaction</u>:
When we <u>balance</u> the reaction we will obtain:
Now, for the enthalpy change, we have to find the <u>standard enthalpy values</u>:
With this in mind, if we <u>multiply</u> the number of moles (in the balanced reaction) by the standard enthalpy value, we can calculate the energy of the <u>reagents</u>:
And the <u>products</u>:
Finally, for the total enthalpy we have to <u>subtract</u> products by reagents :
I hope it helps!