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IceJOKER [234]
2 years ago
10

Newton’s third law of motion is that for every action (force), there is an equal and opposite reaction. Please reword this.

Chemistry
2 answers:
Rashid [163]2 years ago
8 0
If you hit something it hurts in an equal amount that you hurt it
posledela2 years ago
8 0

Answer:

What comes around goes around.

Explanation:

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The pH of a basic solution is 9.77. What is [OH⁻]?
uysha [10]

The  [OH⁻] of the solution is 5.37×10⁵ M.

<h3 /><h3>What is pOH?</h3>

This is the negative logarithm to base 10 of hydroxy ion [OH⁻] concentration.

To calculate the hydroxy ion [OH⁻] concentration we use the formula below.

Note:

  • pH+pOH = 14
  • pOH = 14-pH
  • pOH = 14-9.77
  • pOH = 4.27

Formula:

  • [OH⁻] = 1/10^{pOH}................. Equation 1

Given:

  • pOH = 4.27

Substitute the value into equation 1

  • [OH⁻] = 1/10^{4.27}
  • [OH⁻]  = 5.37×10⁵

Hence, The [OH⁻] of the solution is 5.37×10⁵ M.

Learn more about hydroxy ion concentration here: brainly.com/question/17090407

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2 years ago
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What would be the best way to measure the volume of a small ?​
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You can use a graduated cylinder.
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Plants are capable of using nitrogen directly from the atmosphere. True false
Nataly_w [17]
True I believe because plants require gases which they take from the air.
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Carbon monoxide poisoning is sometimes mistakenly identified as what?
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15A.4(a) What is the temperature of a two-level system of energy separation equivalent to 400 cm−1 when the population of the up
maksim [4K]

Answer:

T = 525K    

Explanation:

The temperature of the two-level system can be calculated using the equation of Boltzmann distribution:

\frac{N_{i}}{N} = e^{-\Delta E/kT}  (1)

<em>where Ni: is the number of particles in the state i, N: is the total number of particles, ΔE: is the energy separation between the two levels, k: is the Boltzmann constant, and T: is the temperature of the system </em>         

The energy between the two levels (ΔE) is:

\Delta E = hck    

<em>where h: is the Planck constant, c: is the speed of light and k: is the wavenumber</em>      

\Delta E = 6.63\cdot 10^{-34} J.s \cdot 3\cdot 10^{8}m/s \cdot 4 \cdot 10^{4}m^{-1} = 7.96 \cdot 10^{-21}J  

Solving the equation (1) for T:

T = \frac{-\Delta E}{k \cdot Ln(N_{i}/N)}  

<em>With Ni = N/3 and k = 1.38x10⁻²³ J/K, </em><em>the temperature of the two-level system is:</em><em> </em>

T = \frac{-7.96 \cdot 10^{-21}J}{1.38 \cdot 10^{-23} J/K \cdot Ln(N/3N)} = 525K                                  

I hope it helps you!

3 0
3 years ago
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