Identify effective techniques for accurate pipet use. Select all that apply. Select one or more: Measure liquid by aligning the
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<u>Answer:</u> The mass of product formed is 79.344 g.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of oxygen = 16.7 g
Molar mass of oxygen = 32 g/mol
Putting values in equation 1, we get:
The chemical reaction for the formation of chromium oxide follows the equation:
By Stoichiometry of the reaction:
3 moles of oxygen produces 3 moles of chromium oxide.
So, 0.522 moles of oxygen will produce = of chromium oxide.
Now, calculating the mass of chromium oxide from equation 1, we get:
Molar mass of chromium oxide = 152 g/mol
Moles of chromium oxide = 0.522 moles
Putting values in equation 1, we get:
Hence, the mass of chromium oxide produced in the given reaction is 79.344 grams.