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olganol [36]
2 years ago
7

What are the Common compounds of niobium in which it is found

Chemistry
1 answer:
blagie [28]2 years ago
7 0

Explanation:

Common Compounds of Niobium Nb

[Nb+3, Nb+5]

Compound NameFormulaMolar Mass

Niobium(III) OxideNb2O3233.811

Niobium(III) SulfateNb2(SO4)3474.0006

Niobium(V) PhosphateNb3(PO4)5753.576

Niobium(V) BromideNbBr5492.4264

Niobium(V) PentoxideNb2O5265.8098

Niobium OxychlorideNbOCl3215.2648

Niobium(V) IodideNbI5727.4287

Niobium(V) PentachlorideNbCl5270.1714

Niobium(V) ThiocyanateNb(SCN)5383.3184

Niobium(III) ChlorideNbCl3199.2654

Niobium(V) Dihydrogen PhosphateNb(H2PO4)5577.84259

Niobium NitrideNbN106.9131

Niobium(III) DichromateNb2(Cr2O7)3833.77676

Niobium HydroxideNb(OH)3143.9284

Niobium(V) PerchlorateNb(ClO4)5590.15938

Niobium(V) HypochloriteNb(ClO)5350.16838

Niobium(III) HypochloriteNb(ClO)3247.26358

Niobium(V) CarbonateNb2(CO3)5485.85726

Niobium(III) TartrateNb2(C4H4O6)3630.02564

Niobium(III) ChromateNb2(CrO4)3533.79386

Niobium(V) HexafluorosilicateNb2(SiF6)5896.192356

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Calcium nitrate tetrahydrate dissolves in cold water to the extent of 266 g per 100 cm3. What is the concentration of nitrate io
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Answer : The correct option is, (b) 22.5 M

Explanation : Given,

Mass of calcium nitrate tetrahydrate = 266 g

Molar mass of calcium nitrate tetrahydrate  = 236.15 g/mole

Volume of solution = 100cm^3=100mL

Molarity : It is defined as the moles of solute present in one liter of solution.

Formula used :

Molarity=\frac{\text{Mass of calcium nitrate tetrahydrate }\times 1000}{\text{Molar mass of calcium nitrate tetrahydrate }\times \text{volume of solution in ml}}

Now put all the given values in this formula, we get:

Molarity=\frac{266g\times 1000}{236.15g/mole\times 100ml}=11.26mole/L=11.26M

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Lithium-6 has a mass of 6.0151 amu and lithium-7 has a mass of 7.0160 amu. The relative abundance of Li-6 is 7.42% and the relat
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Average atomic mass is the weighted average atomic masses with regard to the relative abundance of the isotopes 
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3 0
3 years ago
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Using the following equation: 3H2SO4+ 2Fe -&gt; Fe2(SO4)3+ 3H2
Mariana [72]

Answer:

H₂SO₄

Explanation:

Given data:

Number of moles of H₂SO₄ = 15 mol

Number of moles of Fe = 13 mol

Which reactant is limiting reactant = ?

Solution:

Chemical equation:

3H₂SO₄  + 2Fe      →          Fe₂(SO₄)₃  + 3H₂

now we will compare the moles reactant with product.

               H₂SO₄         :          Fe₂(SO₄)₃  

                  3               :              1

                 15               :              1/3×15 = 5

                H₂SO₄         :            H₂

                  3               :              3

                 15               :              15

                Fe               :          Fe₂(SO₄)₃  

                  2               :              1

                 13               :              1/2×13 = 6.5

                Fe               :                H₂

                  2               :                 3

                 13               :              3/2×13 = 19.5

Number of moles of product formed by  H₂SO₄ are less thus it will act as limiting reactant.

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