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Sloan [31]
2 years ago
6

If 1.2 g of ammonium bicarbonate is treated with .75 grams of sodium chloride, 63.0075 grams sodium bicarbonate will be produced

. In this reaction NaCI is limiting reagent. True or false
Chemistry
1 answer:
Ivan2 years ago
6 0

Answer:

True

Explanation:

Limiting reagent is the reactant that determines the progress of the reaction. It determines how much of the product is formed.

The equation for this reaction is;

NaCl (aq) + NH4HCO3 (aq) → NaHCO3 (aq) + NH4Cl (aq)

From the reaction, 1 mol of NaCl reacts with 1 mol of NH4HCO3 to produce 1 mol of NaHCO3

Converting to masses using; Mass = Number of moles * Molar mass

58.44g of NaCl reacts with 79.056g of NH4HCO3

If we were to  sue the whole 1.2 g of NH4HCO3 we would require xg of NaCl

58.44 = 79.056

x = 1.2

x = 0.887g

The fact that 1.2g of NH4HCO3 requires 0.887g of NaCl (which is less than the available 0.75g) means that NaCl is the limiting reagent.

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En un experimento hacemos reaccionar 12 g de carbono con 32 g de oxígeno para formar dióxido de carbono. Razona si podemos saber
max2010maxim [7]

Answer:

La masa de óxido de carbono iv formado es 44 g.

Explanation:

En esta pregunta, se nos pide calcular la masa de óxido de carbono iv formado a partir de la reacción de masas dadas de carbono y oxígeno.

En primer lugar, necesitamos escribir una ecuación química equilibrada.

C + O2 → CO2

De la ecuación, 1 mol de carbono reaccionó con 1 mol de oxígeno para dar 1 mol de óxido de carbono iv.

Ahora, si marca las masas en la pregunta, verá que corresponde a la masa atómica y la masa molar de la molécula de carbono y oxígeno, respectivamente. ¿Qué indica esto?

Como tenemos una relación molar de 1: 1 en todo momento, lo que esto significa es que la masa de óxido de carbono iv producida también es la misma que la masa molar de óxido de carbono iv.

Por lo tanto, procedemos a calcular la masa molar de óxido de carbono iv Esto es igual a 12 + 2 (16) = 12 + 32 = 44 g Por lo tanto, la masa de óxido de carbono iv formado es 44 g

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What is the reducing agent in the reaction below?
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Covalent bonds can be classified as nonpolar and polar covalent given the electronegativity difference between two atoms (ΔEN).

Nonpolar covalent bond electrons are shared equally between two atoms, polar covalent bond electrons are shared unequally, atoms have partial charges, ionic bond electrons are completely transferred to one atom, full charges present. Therefore, the greater the electronegativity difference, the greater the bond polarity. Let's determine the types of bonds present in the compounds and arrange the ones with polar covalent in order of increasing ΔEN. Sulfur and oxygen are both nonmetals so the substance is covalent. Sulfur has EN = 2.5 and oxygen has EN = 3.5. Since there is an electronegativity difference, the S−O bonds in the substance can be classified as polar covalent bonds.

Learn more about polar covalent bond here:

brainly.com/question/25150590

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