Derive this please as fast as u can
1 answer:
Answer:
Derived in explanation
Explanation:
The law of universal gravitation was discovered by Newton in 1686. According to this law:
“Every object in this universe attracts other body with a force, which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.”
Consider two bodies ‘A’ and ‘B’ having masses ‘m1’ and ‘m2’, respectively. They are placed with their centers at distance ‘r’ from each other.
According to this law, force is directly proportional to the product of their masses, that is:
Also, the force is inversely proportional to the square of the distance between them, that is:
On combining both equations we get:
Where ‘G’ is called ‘Gravitational Constant’ and its value is 6.67 x 10⁻¹¹ Nm²/kg².
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Answer:
Displacement: 6.71 m, Direction: 63.4 degrees north of east
Explanation:
In the attached image we can aprecciate each one of the movements of the parade. Let's say that the parade started from the origin (point (0,0)) then it moves to the east 4 blocks it means now the parade is located at point (4,0).
Then the parade went to the south three blocks, so it moves to the coordinate (4,-3). After this the parade went to the west one block so the new coordinate point is (3, -3).
And finally the movement of the 0 parade was 9 blocks to the north. It means the final point is now (0,9) - (3,-3) = (3,6)
And the displacement will be defined by the folliwing vector operation:
We know that the magnitude of the displacement vector is defined by the phytagoras theorem
And the angle will be defined by:
tan(beta)=3/6
beta = tan^-1(6/3)
beta = 63.43°
