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Luba_88 [7]
3 years ago
14

Calculate the mass of CaCl2 ( formula wt. = 110.99) thatshould

Chemistry
1 answer:
NNADVOKAT [17]3 years ago
7 0

Answer: 5622.6g

Explanation:

Note: Kf for water is 1.86°C/m.

The simple calculation is in the attachment below.

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A condensation reaction forming a glycosidic bond. so in other words a monosaccharide joining together to form a disaccharide. 

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What role does the vulture playing this food web
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scavenger- eats dead carcasses

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Barium-131 is used in the detection of bone tumors. The half-life of barium-131 is approximately 12 days. How long will it take
Evgesh-ka [11]

Barium-131's radiation level won't reach 1/4 of its initial level for 24 hours.

ln[A] t = -kt + ln[A] 0 is the integrated rate rule for the first-order reaction A's products.

A straight line is produced when the natural log of [A] is plotted as a function of time since this equation has the form y = mx + b.

How is the length of a half-life determined?

The amount of time needed for the reactant concentration to drop to half its initial value is known as the half-life of a reaction. A first-order reaction's half-life is a constant that is correlated with its rate constant:

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5 0
1 year ago
True or false
Ivanshal [37]

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4 0
3 years ago
Consider the equilibrium reaction and its equilibrium constant expression. Br 2 ( g ) + 2 NO ( g ) − ⇀ ↽ − 2 NOBr ( g ) K = [ NO
zavuch27 [327]

Answer:

K_2=\frac{[NOBr]^4_{eq}}{[NO]^4_{eq}[Br]^2_{eq}}

Explanation:

Hello,

In this case, for the equilibrium condition, the equilibrium constant is defined via the law of mass action, which states that the division between the concentrations of the products over the concentration of the reactants at equilibrium equals the equilibrium constant, for the given reaction:

2 Br_2 ( g ) + 4 NO ( g ) \rightleftharpoons  4NOBr ( g )

The suitable equilibrium constant turns out:

K_2=\frac{[NOBr]^4_{eq}}{[NO]^4_{eq}[Br]^2_{eq}}

Or in terms of the initial equilibrium constant:

K_2=K_1^2

Since the second reaction is a doubled version of the first one.

Best regards.

5 0
3 years ago
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