First c<span>alculate the mole fraction of each substance:
acetone: 2,88 mol </span>÷ (2,88 mol + 1,45 mol) = 0,665.
cyclohexane: 1,45 ÷ (2,88 mol + 1,45 mol) = 0,335.
Raoult's Law:
P(total) = P(acetone) · χ(acetone) + P(cyclohexane) · χ(cyclohexane).
P(total) = 229,5 torr · 0,665 + 97,6 torr · 0,335.
P(total) = 185,3 torr.
χ for acetone: 229,5 torr · 0,665 ÷ 185,3 torr = 0,823.
χ for cyclohexane: 97,6 torr · 0,335 ÷ 185,3 torr = 0,177.
Answer:
10.1 ms^-2
Explanation:
From;
v = u + at
v = final velocity
u = initial velocity
a= acceleration
t = time taken
To convert the velocity from Km/hr to m/s we us;
x * 1000/3600
Where x is the velocity in Km/hr
So;
799 * 1000/3600 = 221.9 m/s
11325 * 1000/3600 = 3145.8 m/s
4.8 minutes = 4.8 * 60 = 288 s
Applying the formula;
a= v - u/t
a = 3145.8 - 221.9/288
a = 10.1 ms^-2
Explanation:
The question involves converting from one unit (Kilometres) to another unit (Astronomical unit)
The relationship between both units is given as;
1 Km = 6.68459e-9 Au
Kulper belt
6.5 billion km = 6.5e9 Km
1 Km = 6.68459e-9 Au
6.5e9 Km = x
Solving for x;
x = 43.45 Au
Alpha Centauri
44 trillion km = 4.4e13
1 Km = 6.68459e-9 Au
4.4e13 km = x
Solving for x;
x = 294121.83 Au
☃️ Chemical formulae ➝ 
<h3>
<u>How to find?</u></h3>
For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.
<h3>
<u>Solution:</u></h3>
Atomic weight of elements:
Ca = 40
C = 12
O = 16
❍ Molecular weight of
= 40 + 12 + 3 × 16
= 52 + 48
= 100 g/mol
❍ Given weight: 10 g
Then, no. of moles,
⇛ No. of moles = 10 g / 100 g mol‐¹
⇛ No. of moles = 0.1 moles
☄ No. of moles of Calcium carbonate in that substance = <u>0.1 moles</u>
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Answer: i’m not 100% sure but might be active transport
Explanation:
