Question

An object with a mass of 7kg gains the speed 26 meters per second after traveling the distance 2.8m. Calculate the resulting force that acts on it.

Answer 1

Answer:

F = 845 [N]

Explanation:

To solve this problem we must use the following equation of kinematics.

$v_{f} ^{2} =v_{o} ^{2} +2*a*x$

where:

Vf = final velocity = 26 [m/s]

Vo = initial velocity = 0

a = acceleration [m/s²]

x = distance = 2.8[m]

$26^{2} = 0 +(2*a*2.8) \\5.6*a = 676\\a = 120.71[m/s^{2}]$

Now we have to use Newton's second law which tells us that force is equal to the product of mass by acceleration.

ΣF = m*a

where:

F = force [N]

m = mass = 7 [kg]

a = acceleration = 120.71 [m/s²]

$F = 7*120.71\\F = 845 [N]$