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wariber [46]
3 years ago
13

An object with a mass of 7kg gains the speed 26 meters per second after traveling the distance 2.8m. Calculate the resulting for

ce that acts on it.
Physics
1 answer:
jok3333 [9.3K]3 years ago
8 0

Answer:

F = 845 [N]

Explanation:

To solve this problem we must use the following equation of kinematics.

v_{f} ^{2} =v_{o} ^{2} +2*a*x

where:

Vf = final velocity = 26 [m/s]

Vo = initial velocity = 0

a = acceleration [m/s²]

x = distance = 2.8[m]

26^{2} = 0 +(2*a*2.8) \\5.6*a = 676\\a = 120.71[m/s^{2}]

Now we have to use Newton's second law which tells us that force is equal to the product of mass by acceleration.

ΣF = m*a

where:

F = force [N]

m = mass = 7 [kg]

a = acceleration = 120.71 [m/s²]

F = 7*120.71\\F = 845 [N]

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6 0
3 years ago
The wall is 500 sq. feet. A gallon of paint covers 160 sq. feet. What is an appropriate conversion factor to help determine how
lana66690 [7]

Answer:

Explanation:

Given

Wall is 500 ft^2 in area

160\ ft^2 requires 1 gallon of paint

so using unitary method

1\ ft^2 requires \frac{1}{160}   gallon of paint

500 ft^2 wall will require =500\times \frac{1}{160} gallons of paint

=3.0125\ gallons

   

4 0
3 years ago
Which of the following is prohibited by the 2nd law of thermodynamics?
vitfil [10]

(A) A device that converts heat into work with 100% efficiency

It clearly violates the second law of thermodynamics because it warns that while all work can be turned into heat, not all heat can be turned into work. Therefore, despite the innumerable efforts, the efficiencies of the bodies have only been able to reach 60% at present.

6 0
3 years ago
A uniform wooden plank with a mass of 75kg and length of 5m is placed on top of a brick wall so that 1.5m of plank extends beyon
jek_recluse [69]

Answer:

x₂ = 1.33 m

Explanation:

For this exercise we must use the rotational equilibrium condition, where the counterclockwise rotations are positive and the zero of the reference system is placed at the turning point on the wall

            Στ = 0

            W₁ x₁ - W₂ x₂ = 0

where W₁ is the weight of the woman, W₂ the weight of the table.

Let's find the distances.

Since the table is homogeneous, its center of mass coincides with its geometric center, measured at zero.

           x₁ = 2.5 -1.5 = 1 m

The distance of the person is x₂ measured from the turning point, at the point where the board begins to turn the girl must be on the left side so her torque must be negative

            x₂ = \frac{M_1g  }{m_2 g} \ x_1

           

let's calculate

           x₂ = \frac{100}{75}  \ 1

           x₂ = 1.33 m

7 0
3 years ago
Did the displacement at this point reach its maximum of 2 mm before or after the interval of time when the displacement was a co
Igoryamba

Answer:

a. before

Explanation:

Did the displacement at this point reach its maximum of 2 mm before or after the interval of time when the displacement was a constant 1 mm?

from the graph given from a source. the vertical axis represents the displacement of the graph motion, whilst the horizontal side is representing the time variable of the motion .

displacement is distance in a specific direction.

before the displacement was maximum at 2mm was instant at time=0.04s.

But later was constant at 0.06s at a displacement point of 1mm

4 0
3 years ago
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