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elixir [45]
3 years ago
5

The steering wheel of a car has a radius of 0.19 m, and the steering wheel of a truck has a radius of 0.25 m. The same force is

applied in the same direction to each steering wheel. What is the ratio of the torque produced by this force in the truck to the torque produced in the car
Physics
1 answer:
kodGreya [7K]3 years ago
8 0

Answer:

\frac{T_t}{T_c} = 1.32

Explanation:

The torque applied on an object can be calculated by the following formula:

T = Fr

where,

T = Torque

F = Applied Force

r = radius of the wheel

For car wheel:

T_c = Fr_c\\

For truck wheel:

T_t = Fr_t

Dividing both:

\frac{T_t}{T_c} = \frac{Fr_t}{Fr_c}

for the same force applied on both wheels:

\frac{T_t}{T_c} = \frac{r_t}{r_c} \\

where,

rt = radius of the truck steering wheel = 0.25 m

rc = radius of the car steering wheel = 0.19 m

Therefore,

\frac{T_t}{T_c} = \frac{0.25\ m}{0.19\ m} \\

\frac{T_t}{T_c} = 1.32

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a closed systems internal energy changes by 178 j as a result of being heated with 658 j of energy. the energy used to do work b
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<h3><u>Answer;</u></h3>

= 480 Joules

<h3><u>Explanation;</u></h3>

We use the formula, Q - W = ΔU

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7 0
3 years ago
A 1 000-V battery, a 3 000-Ω resistor, and a 0.50-μF capacitor are connected in series with a switch. The time constant for such
vampirchik [111]

Answer:

The current in the circuit at a time interval of τ seconds after the switch has been closed is 0.123 A

Explanation:

The time constant for an R and C in series circuit is given by τ = RC.

R = 3000 ohms, C = 0.5 × 10⁻⁶ F = 5.0 × 10⁻⁷ F

τ = 3000 × 5 × 10⁻⁷ = 0.015 s

The voltage across a capacitor as it charges is given be

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At the point when t = τ, the expassion becomes

V(t = τ) = 1000 (1 - e⁻¹) = 0.632 × 1000 = 632 V

Current flows as a result of potential difference,.

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4 years ago
You place a box weighing 200.2 N on a inclined plane that makes a 37.1 angle with the horizontal. Compute the component of the g
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141.56 N.

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Data given:

Weight of the box= 200.2 N

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