Upward force provided by the branch is 260 N
<u>Explanation:</u>
Given -
Mass of Gibbon, m = 9.3 kg
Length of the branch, r = 0.6 m
Speed of the movement, v = 3.3 m/s
Upward force, T = ?
The tension force in the rod must be greater than the weight at the bottom of the swing in order to provide an upward centripetal acceleration.
Therefore,
F net = T - mg
F net = ma = mv²/r
Thus,
T = mv²/r + mg
T = m ( v²/r + g)
T = 9.3 [ ( 3.3)² / 0.6 + 9.8]
T = 259.9 N ≈ 260 N
Therefore, upward force provided by the branch is 260 N
Answer:
Kg
Explanation:
Given that the definition of intensity is:
The intensity of the beam is defined as the energy delivered per unit area per unit time. That is,
I =( E × t)/A
Which can expressed as
I = J/m^2/s
The S.I Units of
Energy is Joule = kgm^2s^-1
Area A = m^2
Time t = s
Intensity I = kgm^2s^-1 × m^-2 × s
Intensity I = kg
The cubic metres and seconds are cancelled out
Therefore, the S.I units of intensity is kg
The phase angle between the voltages of the capacitor and inductor in rlc circuit is 180°.
The phase angle is the component of a periodic wave. It is the shift between the AC current and the voltage on the measured impedance. The two elements of phase angle are reactance(X) and resistance (R).
The phrase for phase angle is, Xₐ = sinωt
where Xₐ= phase angle
ω = wavelength of the wave in 1 revolution
t = time period of 1 revolution
The instantaneous voltage ΔvR is in phase with the current, ΔvL leads the current by 90°, while ΔvC lags behind the current by 90°. The instantaneous values of these three voltages do add algebraically to give the instantaneous voltages across the RLC combination.
Learn more about phase angle here brainly.com/question/14391865
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Answer:
Radius of curvature of the mirror = 250 cm
Explanation:
Given:
Object distance from mirror = 250 cm (u=-250)
Object distance appears in mirror = 250 cm (v=-250)
Find:
Radius of curvature of the mirror
Computation:
Using mirror formula
1/f = 1/v + 1/u
1/f = 1/(-250) + 1/(-250)
f = (-250/2)
f = -125 cm or 125 cm
Radius of curvature of the mirror = 2(f)
Radius of curvature of the mirror = 2(125)
Radius of curvature of the mirror = 250 cm
Answer:
C = 0.0125 m/s⁴. The calculation procedure can be found in the attachment below. The concept of motion along a straight line with constant acceleration has been applied to solve the problem.
Explanation:
The sign convention chosen in this problem solution is upwards as positive and downwards negative. The equation of motion v = u + at has been used to calculate the constant C as only one unknown is contained in this equation. This is so because we have been given the initial velocity, the acceleration and the time taken. To solve future problems of this kind, first thing to check for is an equation of motion with the least number of unknown. This helps to reduce the complexity of the problem solution.
