Question

12. A baseball (m = 0.14 kg) with initial velocity of -40 m/s (90 mph) is hit. It leaves the bat with a velocity of 60m/s after 0.001s. What is the impulse and average net force applied to the ball by the bat? ​

Answer 1

Answer:

the impulse is 14 kg-m/s and the net force applied is 14000 N

Explanation:

Given that,

The mass of a baseball, m = 0.14 kg

Initial velocity of the baseball, u = -40 m/s

Final velocity, v = 60 m/s

Time, t = 0.001 s

We need to find the impulse and average net force applied to the ball by the bat.

Impulse = change in momentum

i.e.

J = m(v-u)

J = 0.14 × (60-(-40))

J = 14 kg-m/s

Now,

J = Ft

F is average force applied to the ball

So,

$F=\dfrac{J}{t}\\\\F=\dfrac{14}{0.001}\\\\F=14000\ N$

So, the impulse is 14 kg-m/s and the net force applied is 14000 N.