The chemical reaction would be:
C3H8 + 5O2 = 3CO2 + 4H2O
For this case, we assume that gas is ideal thus in every 1 mol the volume would be 22.41 L. We calculate as follows:
28.7 L C3H8 ( 1 mol / 22.41 L ) ( 4 mol H2O / 1 mol C3H8 ) ( 18.02 g / mol ) = 92.31 g H2O produced
Hope this answers the question.
D bc they actually contacted each other
PV=nRT<=> P=nRT/V=2,40*R*(273+97)/45 atm.
Calculate it. R is a number that is given, find it and use your math to solve.
Answer:
Mass = 159.8 g
Explanation:
Given data:
Mass of HNO₂ = ?
Moles of nitrous acid = 3.4 mol
Solution:
Formula:
Number of moles = mass / molar mass
We will rearrange this formula.
Mass = number of moles × molar mass
Molar mass of nitrous acid = 47 g/ mol
Mass = 3.4 mol × 47 g/ mol
Mass = 159.8 g
