Answer:
0 N, 3.49 m/s
Explanation:
Draw a free body diagram for the bucket at the top of the swing. There are two forces acting on the bucket: weight and tension, both downwards.
If we take the sum of the forces in the radial direction, where towards the center is positive:
∑F = ma
W + T = m v² / r
The higher the velocity that Rony swings the bucket, the more tension there will be. The slowest he can swing it is when the tension is 0.
W = m v² / r
mg = m v² / r
g = v² / r
v = √(gr)
Given that r = 1.24 m:
v = √(9.8 m/s² × 1.24 m)
v = 3.49 m/s
Answer:
Acceleration is the change in velocity divided by time
Explanation:
This is the correct answer because distance divided by time is the position. Speed multiplied by time is the distance. And acceleration is not just velocity, but the change in velocity over time.
Answer:
Acceleration of the ship, ![a=2.14\times 10^{-7}\ m/s^2](https://tex.z-dn.net/?f=a%3D2.14%5Ctimes%2010%5E%7B-7%7D%5C%20m%2Fs%5E2)
Explanation:
It is given that,
Mass of both ships, ![m=39000\ metric\ tons=39\times 10^6\ kg](https://tex.z-dn.net/?f=m%3D39000%5C%20metric%5C%20tons%3D39%5Ctimes%2010%5E6%5C%20kg)
Distance between two ships, d = 110 m
The gravitational force between two ships is given by :
![F=G\dfrac{m^2}{d^2}](https://tex.z-dn.net/?f=F%3DG%5Cdfrac%7Bm%5E2%7D%7Bd%5E2%7D)
![F=6.67\times 10^{-11}\ Nm^2/kg^2\times \dfrac{(39\times 10^6\ kg)^2}{(110\ m)^2}](https://tex.z-dn.net/?f=F%3D6.67%5Ctimes%2010%5E%7B-11%7D%5C%20Nm%5E2%2Fkg%5E2%5Ctimes%20%5Cdfrac%7B%2839%5Ctimes%2010%5E6%5C%20kg%29%5E2%7D%7B%28110%5C%20m%29%5E2%7D)
F = 8.38 N
Let a is the acceleration. Now, using second law of motion as :
![a=\dfrac{F}{m}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7BF%7D%7Bm%7D)
![a=\dfrac{8.38\ N}{39\times 10^6\ kg}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B8.38%5C%20N%7D%7B39%5Ctimes%2010%5E6%5C%20kg%7D)
![a=2.14\times 10^{-7}\ m/s^2](https://tex.z-dn.net/?f=a%3D2.14%5Ctimes%2010%5E%7B-7%7D%5C%20m%2Fs%5E2)
So, the acceleration of either ship due to the gravitational attraction of the other is
. Hence, this is the required solution.
Answer:
sorry about the other person but its b
Explanation:
Answer:
α = 0.0135 rad/s²
Explanation:
given,
t = 133 min = 133 x 60 = 7980 s
angular speed varies from 570 rpm to 1600 rpm
now,
570 rpm = ![570 \times \dfrac{2\pi}{60}](https://tex.z-dn.net/?f=570%20%5Ctimes%20%5Cdfrac%7B2%5Cpi%7D%7B60%7D)
= 59.69 rad/s
1600 rpm = = ![570 \times \dfrac{2\pi}{60}](https://tex.z-dn.net/?f=570%20%5Ctimes%20%5Cdfrac%7B2%5Cpi%7D%7B60%7D)
= 167.6 rad/s
using equation of rotational motion
ωf = ωi + αt
167.6 = 59.7 + α x 7980
α x 7980 = 107.9
α = 0.0135 rad/s²