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hram777 [196]
4 years ago
7

Does water boil at the same temperature everywhere

Chemistry
2 answers:
Zepler [3.9K]4 years ago
8 0
No, Water boils faster at higher altitudes.
Marizza181 [45]4 years ago
8 0

Answer:

No, Water boils faster at higher altitudes.

Explanation:

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Based on the data given, which factor had the greatest effect on the behavior of the gas
Pepsi [2]
Do you have the picture of the data?
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4 years ago
The picture shown depicts many microscopic organisms that can live in extreme environments such as hot springs and
stealth61 [152]

Answer: archaebacteria

Explanation: I took the same test

3 0
3 years ago
Hoeveel gram opgeloste stof moet je afwegen om 250 ml KMnO4-oplossing te bereiden met een concentratie van 0,500 mol / L
Hatshy [7]

How many grams of solute do you have to weigh to prepare 250 ml KMnO4 solution with a concentration of 0.500 mol / L

Answer:

19.75g

Explanation:

Given parameters:

Volume of KMnO₄  = 250mL or 0.25L

Concentration of solution  = 0.5mol/L

Unknown:

Mass of solute or  KMnO₄ = ?

Solution:

To solve this problem, we need to find the number of moles first.

 Number of moles  = Concentration  x volume

 Number of moles  = 0.5mol/L x 0.25L  = 0.125mol

So;

   Mass in grams  = number of moles x molar mass

 Molar mass of  KMnO₄ = 39 + 55 + 4(16)  = 158g/mol

   Mass in grams  = 0.125 x 158  = 19.75g

7 0
3 years ago
Read 2 more answers
The following reactions are used in batteries:Reaction I is used in fuel cells, II in the automobile lead-acid battery, and III
elixir [45]

The highest ratio is -0.613kj/g which is for automobile lead-acid battery .

Given ,

Reaction-1 used in fuel cells

Reaction-2 used in automobile lead-acid battery

Reacttion-3 used in experimental high-temperature battery for powering electric vehicles .

1) Fuel cells :

2H2(g) + O2(g) ==> 2H20 (l)   ,    E^0cell = 1.23V

We know ,

Free energy is the maximum work done .

delta G = Wmax

=> Wmax = delta G = -4.75*10^5j/mol e^- = -4.75*10^2 kj/ mol e^-

Molecular mass of 1 mole of H2  = 2 .016 g / mol e^-

Molecular mass of 2 mole of H2 = 4.032 g/mol e^-

Molecular mass of O2 = 32 g/mol e^-

Total mass of the reactants = (4.032+32)g/mol e^- = 36.032 g/mol e^-

Ratio of Wmax to the total mass of the reactants

=Wmax/ total mass of the reactants

=( -4.75*10^2 kj/mol e^-)/36.032 g/mol e^-

=-13.2kj/g

Therefore , the ratio of Wmax to total mass of the reactants is -13.2kj/g .

2) Automobile lead-acid battery :

Pb(s) + PbO2(s) + 2H2SO4(aq) ==> 2PbSO4 (s) + 2H2O (l)  ,  E^0cell = 2.04V

We know ,

Wmax = delta G = -3.94*10^5j/mol e^- = -3.94*10^2kj/mol e^-

molecular mass of Pb = 207.2 g /mol e^-

molecular mass of Pbo2 = 239.2g/mol e^-

molecular mass of H2SO4 = 98.008g/mol e^-

molecular mass of 2 mole of H2SO4 = 196.016g/mol e^-

total mass of the reactants = (207.2+239.2+196.016)g/mol e^- = 642.416g/mol e^-

Ratio of Wmax to total mass of the reactants

= Wmax/total mass of reactants

=(-3.94*10^2kj/mol e^-)/642.416g/mol e^-

=-0.613kj/g

Hence ,the ratio of Wmax to the total mass of the reactants of automobile lead-acid battery is -0.613kj/g .

3) Experimental high temperature battery :

2Na(l) +FeCl2(s) ==> 2NaCl (s) + Fe(s)     ,     E^0 cell = 2.35V

We know ,

Wmax = delta G = -4.53*10^5j/mol e^- = -4.53*10^2kj/mol e^-

molecular mass of Na = 22.99 g/mol e^-

molecular mass of 2 moles of Na = 45.98g/mol e^-

molecular mass of FeCl2 = 126.85 g/mol e^-

total mass of the reactants =( 45.98+ 126.85)g/mol e^- = 172.83 g/mol e^-

Ratio of Wmax to the total mass of the reactants

= Wmax / total mass of reactants

=(-4.53*10^2kj/mol e^-)/ 172.83g/mol e^-

=-2.62kj/g

Therefore , the ratio of Wmax to the total mass of the reactants in an experimental high temperature battery is -2.62kj/g .

Hence , the highest ratio is -0.613kj/g which is of lead -acid battery .

Learn more about fuel cell here :

brainly.com/question/13603874

#SPJ4

4 0
2 years ago
A 3.28 L solution is prepared by dissolving 535 g CaCl2 in water. The molar mass of CaCl2 is 110.98 g. What is the morality of t
andrey2020 [161]

Answer:

              1.47 mol/L

Explanation:

Molarity is given as,

                           Molarity = Moles / Vol in L    ------- (1)

Moles of CaCl₂,

                           Moles = Mass / M.Mass

                           Moles = 535 g / 110.98 g/mol

                           Moles = 4.82 mol

Now, putting values in eq. 1.

                           Molarity = 4.82 mol / 3.28 L

                           Molarity = 1.47 mol/L

5 0
2 years ago
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