There are some missing data in the text of the problem. I've found them online:
a) coefficient of friction dry steel piston - steel cilinder: 0.3
b) coefficient of friction with oil in between the surfaces: 0.03
Solution:
a) The force F applied by the person (300 N) must be at least equal to the frictional force, given by:
![F_f = \mu N](https://tex.z-dn.net/?f=F_f%20%3D%20%5Cmu%20N)
where
![\mu](https://tex.z-dn.net/?f=%5Cmu)
is the coefficient of friction, while N is the normal force. So we have:
![F=\mu N](https://tex.z-dn.net/?f=F%3D%5Cmu%20N)
since we know that F=300 N and
![\mu=0.3](https://tex.z-dn.net/?f=%5Cmu%3D0.3)
, we can find N, the magnitude of the normal force:
![N= \frac{F}{\mu}= \frac{300 N}{0.3}=1000 N](https://tex.z-dn.net/?f=N%3D%20%5Cfrac%7BF%7D%7B%5Cmu%7D%3D%20%5Cfrac%7B300%20N%7D%7B0.3%7D%3D1000%20N%20%20)
b) The problem is identical to that of the first part; however, this time the coefficienct of friction is
![\mu=0.03](https://tex.z-dn.net/?f=%5Cmu%3D0.03)
due to the presence of the oil. Therefore, we have:
Its when the animal repeats what it is taught similar to a child you never really teach them to lie it just happens because they have seen other people do it
Answer:
5295.3 N
Explanation:
According to law of momentum conservation, the change in momentum of the ball shall be from the momentum generated by the batter force
mv + P = mV
P = mV - mv = m(V - v)
Since the velocity of the ball before and after is in opposite direction, one of them is negative
P = 0.14(44.8 - (-19.5)) = 9 kg m/s
Hence the force exerted to generate such momentum within 1.7ms (0.0017s) is
F = P/t = 9/0.0017 = 5295.3 N
Answer:
8
Explanation:
Ca(ClO2)2 - 2*2 = 4 Oxygen atoms
2 Ca(ClO2)2 - 2*4 = 8 Oxygen atoms
Answer:
Hey guess what there's no question genius
Explanation: