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Jobisdone [24]
3 years ago
5

How many 10" diameter circles can be cut from a semicircular shape that has a 20"

Engineering
2 answers:
Iteru [2.4K]3 years ago
5 0

Answer:

<h2> 1</h2>

  • <em>The</em><em> </em><em>diameter</em><em> </em><em>measurement</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>semi circle</em><em> </em><em>having</em><em> </em><em>a</em><em> </em><em>measure</em><em> </em><em>of</em><em> </em><em>1</em><em>0</em><em>"</em><em> </em><em>diameter</em><em> </em><em>,</em><em> </em><em>2</em><em>0</em><em>"</em><em> </em><em>diameter</em><em> </em><em>and</em><em> </em><em>a</em><em> </em><em>length</em><em> </em><em>of</em><em> </em><em>2</em><em>5</em><em>.</em>
N76 [4]3 years ago
3 0

9514 1404 393

Answer:

  1

Explanation:

Only one such circle can be drawn. The diameter of the 10" circle will be a radius of the semicircle. In order for the 10" circle to be wholly contained, the flat side of the semicircle must be tangent to the 10" circle. There is only one position in the figure where that can happen. (see attached).

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Explanation:

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Many farms and ranches use electric fences to keep animals from getting into or out of specific pastures. When switched on, an e
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Answer:

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Explanation:

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3 years ago
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Consider a resistor made of pure silicon with a cross-sectional area pf 0.5 μm2, and a length of 50 μm. What is the resistance o
lukranit [14]

Answer: 24 pA

Explanation:

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Based on these considerations, we found that at room temperature, pure silicon resistivity can be approximated as 2.1. 10⁵  Ω  cm.

The resistance R of a given resistor, is expressed by the following formula:

R = ρ L / A

Replacing by the values for resistivity, L and A, we have

R = 2.1. 10⁵ Ω  cm. (10⁴ μm/cm). 50 μm/ 0.5 μm2

R = 2.1. 10¹¹ Ω

Assuming that we can apply Ohm´s Law, the current that would pass through this resistor for an applied voltage of 5 V, is as follows:

I = V/R = 5 V / 2.1.10¹¹ Ω = 2.38. 10⁻¹¹ A= 24 pA

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3 years ago
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