Answer:
Explanation:
Formula for the calculation of no. of Mol is as follows:
Molecular mass of Ag = 107.87 g/mol
Amount of Ag = 5.723 g
Molecular mass of S = 32 g/mol
Amount of S = 0.852 g
Molecular mass of O = 16 g/mol
Amount of O = 1.695 g
In order to get integer value, divide mol by smallest no.
Therefore, divide by 0.02657
Therefore, empirical formula of the compound =
Answer:
I needed to use good precision in my measurement for my chemistry lab
Explanation:
We have to complete all the given reactions.
1. Fe(s) + CuCl₂ → Cu + FeCl₂
2. Cu(s) + FeCl₂(aq) → NR (no reaction takes place)
3. K(s) + NiBr2(aq) → NR (no reaction takes place)
4. Ni(s) + KBr(aq) → K + NiBr₂
5. Zn(s) + Ca(NO₃)₂(aq) → NR (no reaction)
6. Ca(s) + Zn(NO₃)₂(aq) → Zn(s) + Ca(NO₃)₂(aq)
C) and d) are physical changes while b) is chemical
Answer:
120 V usually but its not given in the option so 110 V
