1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SOVA2 [1]
3 years ago
15

Calculate the electrostatic force between two protons separated by a distance of 0.90 m

Physics
1 answer:
cluponka [151]3 years ago
6 0
Use F = (9x10^9 x 1.6x10^-19x 1.6x10^-19) / (0.9 x 0.9)
You might be interested in
Which snack is an excellent choice for protein, B vitamins, vitamin E, and healthful fat
igomit [66]
Fruits and frozen fruit bars is the correct answer.
7 0
3 years ago
Read 2 more answers
How long does a lunar eclipse last? A)seconds B)Minutes C)Days D) Weeks
bonufazy [111]
Well, it happens a few weeks ahead, then for a total of 3 hours and 40 minutes.
3 0
3 years ago
Not in book
umka2103 [35]

Answer:

x=2.4365\ m

and

x=-1.4365\ m

Explanation:

Given:

  • first charge, q_1=5\times 10^{-3}\ C
  • second charge, q_2=3\times 10^{-3}\ C
  • position of first charge, x_1=-2\ m
  • position of second charge, x_2=-1\ m

Now since there are only 2 charges and of the same sign so they repel each other. This repulsion will be zero at some point on the line joining the charges.

<u>Now, according to the condition, electric field will be zero where the effects of field due to both the charges is equal.</u>

E_1=E_2

  • since first charge is greater than the second charge so we may get a point to the right of the second charge and the distance between the two charges is 1 meter.

\frac{1}{4\pi.\epsilon_0} \frac{q_1}{(r+1)^2} =\frac{1}{4\pi.\epsilon_0} \frac{q_2}{(r)^2}

\frac{5\times 10^{-3}}{(r+1)^2} = \frac{3\times 10^{-3}}{(r)^2}

3(r^2+1+2r)=5r^2

2r^2-6r-3=0

r=3.4365 \&\ r=-0.4365

Since we have assumed that the we may get a point to the right of second charge so we calculate with respect to the origin.

x=-1+3.4365=2.4365\ m

and

x=-1-0.4365=-1.4365\ m

6 0
2 years ago
Suppose the coefficient of static friction between a quarter and the back wall of a rocket car is 0.330. At what minimum rate wo
Helga [31]

Answer:3.23 m/s^2

Explanation:

Given

\mu_s =0.330

Frictional Force is balanced by force due to car acceleration

Frictional force F_s

F_s=ma_{min}

\mu_sN=ma_{min}

\mu_s\cdot mg=ma_{min}

a_{min}=\mu_s \cdot g=0.330\times 9.8=3.23 m/s^2

6 0
2 years ago
30.6*X+-2.56<br> Pls help
pochemuha

Answer:  10.16

Explanation:

5 0
2 years ago
Other questions:
  • Odyssey Quiz
    10·1 answer
  • Josh starts at a position of x=0 meters at the left side of the front of the classroom. Over the course of the class he walks ba
    14·1 answer
  • A car travels 3 km north, then turns and travels 4 km west. What is the car's<br> displacement?
    14·2 answers
  • 3. A -4.00-uC charge lies 20.0cm to the right of a 2.00-uC charge on the x axis. What is the force on the 2.00-uC charge?
    13·1 answer
  • A car travelled a distance of 348 km in 6.0 hours. What was it’s speed in (a) km/h and (b) m/sec?
    12·1 answer
  • How much electricity is used to boil 600 g of water if the kettle has a power of 1500 W? The water boiled for 3 minutes and 9 se
    13·1 answer
  • Does the Sun actually turn dark during a total solar eclipse? Why or why not?
    6·2 answers
  • When cell A sends a message to
    11·1 answer
  • I am the only non-metal in Group 14. Who am I?
    14·1 answer
  • How far does a car travel in 10 s if its initial velocity is 3 m/s and its acceleration
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!