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3 years ago

1. 55 grams of salt are added to 100 L of water to make a saline solution.

Chemistry

1 answer:

IRISSAK [1]3 years ago

8 0

Answer:

0.55g/L

Explanation:

Given parameters;

Mass of salt = 55g

Volume of water = 100L

Unknown:

g/L concentration = ?

Solution:

To solve this problem, we must understand that concentration is the amount of solute per solution

g/L concentration = $\frac{55}{100}$ = 0.55g/L

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Leni [432]

Answer : The molar mass of solute is, 89.9 g/mol

Explanation : Given,

Mass of solute = 5.8 g

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Formula used :

$\Delta T_f=K_f\times m\\\\T_f^o-T_f=T_f\times\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of water}}$

where,

$\Delta T_f$ = change in freezing point

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m = molality

Now put all the given values in this formula, we get

$(0^oC)-(1.20^oC)=1.86^oC/m\times \frac{5.8g\times 1000}{\text{Molar mass of solute}\times 100g}$

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3 years ago