Ask question

Ask question

All categories

2 years ago

14

A 450-N rightward force is used to drag a large box across the floor with a constant velocity of 1.2 m/s. The coefficient of fri

ction between the box and the floor is 0.795. Determine the mass of the box.

1 answer:

Nikolay [14]2 years ago

8 0

Answer:

the mass of the box is 51.98 kg.

Explanation:

Given;

applied horizontal force, F = 450 N

coefficient of friction, μ = 0.795

constant velocity, v = 1.2 m/s

At constant velocity, the acceleration of the object is zero and the net force will be zero.

$F_{Net} = F - F_k\\\\0 = F - F_k\\\\F_k = F\\\\\mu \ N = F\\\\\mu (mg) = F\\\\m = \frac{F}{\mu g} \\\\m = \frac{405}{0.795 \ \times \ 9.8} \\\\m = 51.98 \ kg$

Therefore, the mass of the box is 51.98 kg.

You might be interested in

In a large restaurant an average 60% customers ask for water with their meal. A random sample of 10 customers is selected. Find

Gekata [30.6K]

Answer:

a) $P(6)=0.25$

b) $p(x$

c) $p(x\geq3)=0.9878$

d) $\sigma=\sqrt{2.4}=1.5492$

Explanation:

From the question we are told that:

Population percentage $p_\%=\60%$

Sample size $n=10$

Let x =customers ask for water

Let y =customers dose not ask for water with their meal

Generally the equation for y is mathematically given by

$y=1-p_\%\\y=1-0.60\\y=0.40$

Generally the equation for pmf p(x) is mathematically given by

$P(x)=10C_x (0..6)^x(0.4)^{10-x}$

a)

Generally the probability that exactly 6 ask for water is mathematically given by

$P(x)6=10C_6 (0..6)^6(0.4)^{10-6}$

$P(6)=0.25$

b)

Generally the probability that less than 9 ask for water with meal is mathematically given by

$p(xg)$

$p(x$

$p(x$

$p(x$

c)

Generally the probability that at least 3 ask for water with meal is mathematically given by

$p(x\geq3)=1-p(x$

$p(x\geq3)=1-[p(0)+p(1)+p(2)]$

$p(x\geq3)=1-[0.00001+0.0015+0.0106]$

$p(x\geq3)=1-[0.0122]$

$p(x\geq3)=0.9878$

d)

Generally the mean and standard deviation of sample size is mathematically given by

Mean

$\=x=np=10(0.6)=6$

Standard deviation

$v(x)=npq=10(0.6)(0.4)=2.4$

$\sigma=\sqrt{2.4}=1.5492$

4 0

3 years ago

A harmonic wave is traveling along a rope. It is observed that the oscillator that generates the wave completes 37.0 vibrations

Goryan [66]

Answer:

0.47 m

Explanation:

$N$ = Number of vibrations = 37

$t$ = total time taken = 33 s

$T$ = time period of each vibration

frequency of vibration is given as

$f = \frac{N}{t} \\f = \frac{37}{33} \\f = 1.12$ Hz

$d$ = distance traveled along the rope = 421 cm = 4.21 m

$t$ = time taken to travel the distance = 8 s

$v$ = speed of the wave

Speed of the wave is given as

$v = \frac{d}{t}\\v = \frac{4.21}{8}\\v = 0.53 ms^{-1}$

$\lambda$ = wavelength of the harmonic wave

wavelength of the harmonic wave is given as

$\lambda = \frac{v}{f} \\\lambda = \frac{0.53}{1.12} \\\lambda = 0.47 m$

8 0

2 years ago

Read 2 more answers

A stone that starts at rest free falls for 7.0 s. How far does the stone fall in this time?

vredina [299]

Gravitational acceleration is approx 9.8 m/s
Time is 7s

a=9.8 m/s
t=7s

a = d/t^2

therefore:

d = a * t^2

d = 9.8 * 7^2

d = 9.8 * 49

d = 480.2 [m]

7 0

3 years ago

The average adult in the US watches _____ hours of television each week.

Shkiper50 [21]

The average adult in the us spends 24 hours watching televistion each week

8 0

3 years ago

Read 2 more answers

what would the mass be of an object that was moving at a velocity of 35 m/s and has a kinetic energy of 500j be?

bearhunter [10]

Answer:

0.816 kg

Explanation:

$E_k=\frac{1}{2}mv^{2}\\$

so $m=\frac{2E_k}{v^2}=\frac{2\times500}{35^2}=0.816 kg$

5 0

2 years ago