Answer:
v = 11.1m/s
Vx = 7.19m/s
Vy = 8.45m/s
V(sedan) = 30.4m/s
V(suv) = 25.9m/s
Explanation:
A 450-N rightward force is used to drag a large box across the floor with a constant velocity of 1.2 m/s. The coefficient of fri
1 answer:
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Answer:
It covers distance of 9.15 football fields in the said time.
Explanation:
We know that
Thus distance covered in blinking of eye =
Thus no of football fields=
Answer:
The velocity of the student has after throwing the book is 0.0345 m/s.
Explanation:
Given that,
Mass of book =1.25 kg
Combined mass = 112 kg
Velocity of book = 3.61 m/s
Angle = 31°
We need to calculate the magnitude of the velocity of the student has after throwing the book
Using conservation of momentum along horizontal direction
Put the value into the formula
Hence, The velocity of the student has after throwing the book is 0.0345 m/s.
Answer:
acceleration 8 km/h/s south
Explanation:
First of all, let's remind that a vector quantity is a quantity which has both a magnitude and a direction.
Based on this definition, we can already rule out the following two choices:
distance: 40 km
speed: 40 km/h
Since they only have magnitude, they are not vectors.
Then, the following option:
velocity: 5 km/h north
is wrong, because the car is moving south, not north.
So, the correct choice is
acceleration 8 km/h/s south
In fact, the acceleration can be calculated as
where
v = 40 km/h is the final velocity
u = 0 is the initial velocity
t = 5 s is the time
Substituting,
And since the sign is positive, the direction is the same as the velocity (south).
Data:
h = 2m
m = 45 Kg
PE = ? (Joule)
Adopting, gravity (g) ≈ <span>9,8 m/s²
</span>
Formula:
Solving:
Answer:
<span>The sled's potential energy is 882 Joules</span>
h = 2m
m = 45 Kg
PE = ? (Joule)
Adopting, gravity (g) ≈ <span>9,8 m/s²
</span>
Formula:
Solving:
Answer:
<span>The sled's potential energy is 882 Joules</span>