A 0.99 kg object is suspended from a spring scale and submerged in a liquid. The reading on the scale is 2.15 N. Calculate the b
1 answer:
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To place the poles of a 1. 5 v battery to achieve the same electric field is 1.5×10−2 m
The potential difference is related to the electric field by:
∆V=Ed
where,
∆V is the potential difference
E is the electric field
d is the distance
what is potential difference?
The difference in potential between two points that represents the work involved or the energy released in the transfer of a unit quantity of electricity from one point to the other.
We want to know the distance the detectors have to be placed in order to achieve an electric field of
E=1v/cm=100v/cm
when connected to a battery with potential difference
∆v=1.5v
Solving the equation,we find
learn more about potential difference from here: brainly.com/question/28166044
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Explanation:
Given that,
Two resistors of resistance 6 ohm and 3 ohm are connected in series and then in parallel.
For series combination,
For parallel combination,
When 6 ohm and 3 ohm are in series,
When 6 ohm and 3 ohm are in paralle,
So, the equivalent resistance in series combination is 9 ohms and in parallel combination it is 2 ohms.