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3 years ago

An 12 kg mass and a 18 kg mass experience a force of gravity pulling the balls towards each other of

Physics

1 answer:

Inessa [10]3 years ago

4 0

Answer:

$5.5\:\mathrm{m}$

Explanation:

We can use Newton's Universal Law of Gravitation to solve this:

$F=G\frac{m_1m_2}{r^2}$ ,

Plugging in given values, we have the equation:

$4.7\cdot 10^{-10}=6.67\cdot 10^{-11}\cdot \frac{12\cdot 18}{r^2}$ .

Solving, we get:

$r^2=30.6536,\\r=\fbox{$5.5\:\mathrm{m}$}$ .

You might be interested in

What force causes weight? How is weight affected as an object moves farther away from the center of the earth?

stich3 [128]

Gravity affects weight of an object

Its weight reduces as it moves away from the center as gravity is strongest near the core and reduces as you move away

Hope this helps C:

3 0

3 years ago

Read 2 more answers

A 120-kg object and a 420-kg object are separated by 3.00 m At what position (other than an infinitely remote one) can the 51.0-

djverab [1.8K]

Answer:

1.045 m from 120 kg

Explanation:

m1 = 120 kg

m2 = 420 kg

m = 51 kg

d = 3 m

Let m is placed at a distance y from 120 kg so that the net force on 51 kg is zero.

By use of the gravitational force

Force on m due to m1 is equal to the force on m due to m2.

$\frac{Gm_{1}m}{y^{2}}=\frac{Gm_{2}m}{\left ( d-y \right )^{2}}$

$\frac{m_{1}}{y^{2}}=\frac{m_{2}}{\left ( d-y \right )^{2}}$

$\frac{3-y}{y}=\sqrt{\frac{7}{2}}$

3 - y = 1.87 y

3 = 2.87 y

y = 1.045 m

Thus, the net force on 51 kg is zero if it is placed at a distance of 1.045 m from 120 kg.

6 0

3 years ago

Which law of motion accounts for the following statement? "A ball hit by a man travels faster than one hit by a boy."

kifflom [539]

A ball hit by a man is stronger than a ball hit by a man because the man uses more force when hitting the ball than the boy does.

5 0

3 years ago

Read 2 more answers

In a physics experiment, two equal-mass carts roll towards each other on a level, low-friction track. One cart rolls rightward a

xz_007 [3.2K]

Answer:

The correct answer is option a.

Explanation:

Conservation of momentum :

$m_1u_1+m_2u_2=m_1v_1+m_1v_2$

Where :

$m_1, m_2$ = masses of object collided

$u_1,u_2$ = initial velocity before collision

$v_1,v_2$ = final velocity after collision

We have :

Two equal-mass carts roll towards each other.

$m_1=m_2=M$

Initial velocity of $m_1=u_1=2 m/s$

Initial velocity of $m_2=u_2=-1 m/s$ (opposite direction)

Final velocity of $m_1=v_1=v$ (same direction )

Final velocity of $m_2=v_2=v$ (same direction)

$M\times 2 m/s+M(-1 m/s)=Mv+Mv$

$1 m/s=2v$

v = 0.5 m/s

rg135

The speed of the carts after their collision is 0.5 m/s.

7 0

3 years ago

Will give brainlist

Aleks [24]

Answer:

Yes

Explanation:

There was a force, 500 lb.

and a motion in the direction of the force, in this case a negative direction.

Therefore the lifter did negative work on the mass of the barbell against gravity.

Gravity would do positive work against the mass of weight when the lifter lowers the barbell as the force vector and the motion vector are in the same direction.

5 0

3 years ago